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Tju [1.3M]
4 years ago
9

1/3h-4(2/3h-3)=2/3h-6

Mathematics
2 answers:
serious [3.7K]4 years ago
7 0
\frac{1}{3}h -4(\frac{2}{3}h-3^{(3})=\frac{2}{3}h-6^{(3} \\\\ \frac{h}{3} -4*\frac{2h-9}{3}=\frac{2h-18}{3} \\\\ h-4(2h-9)=2h-18 \\\\ h-8h+36=2h-18 \\\\ -7h+36=2h-18 \\\\ -7h-2h=-18-36 \\\\ -9h=-54 \\\\ \boxed{h=\frac{-54}{-9}=6}
Elena-2011 [213]4 years ago
6 0
\frac{1}{3}h-4(\frac{2}{3}h-3)=\frac{2}{3}h-6\ \ \ \ |multiply\ by\ 3\\\\
h-4(2h-9)=2h-18\\\\
h-8h+36=2h-18\\\\
-7h+36=2h-18\ \ \ |subtract\ 2h\\\\
-9h+36=-18\ \ \ |subtract\ 36\\\\
-9h=-54\ \ \ |divide\ by\ -9\\\\
h=6
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Step-by-step explanation:

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4 + (-8) ___ 6 + (-8) + (-6)

If the signs are the same, you add. If you have one positive and one negative sign, you minus:

4 + (-8) = 4 - 8 = -4

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Answer:

\\ \gamma= \frac{a\cdot b}{b\cdot b}

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if b \neq 0. Recall that given two vectors a,b  a⊥ b if and only if a\cdot b =0 where \cdot is the dot product defined in \mathbb{R}^n. Suposse that b\neq 0. We want to find γ such that (a-\gamma b)\cdot b=0. Given that the dot product can be distributed and that it is linear, the following equation is obtained

(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b

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4 years ago
Can an equation with the variable on both sides be written as a two step equation
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Answer:

·         Use properties of equality together to isolate variables and solve algebraic equations.

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Introduction

 

There are some equations that you can solve in your head quickly. For example – what is the value of y in the equation 2y = 6? Chances are you didn’t need to get out a pencil and paper to calculate that y = 3. You only needed to do one thing to get the answer, divide 6 by 2.

 

Other equations are more complicated. Solving  without writing anything down is difficult! That’s because this equation contains not just a variable but also fractions and terms inside parentheses. This is a multi-step equation, one that takes several steps to solve. Although multi-step equations take more time and more operations, they can still be simplified and solved by applying basic algebraic rules.

 

Using Properties of Equalities

 

Remember that you can think of an equation as a balance scale, with the goal being to rewrite the equation so that it is easier to solve but still balanced. The addition property of equality and the multiplication property of equality explain how you can keep the scale, or the equation, balanced. Whenever you perform an operation to one side of the equation, if you perform the same exact operation to the other side, you’ll keep both sides of the equation equal.

 

If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division.

 

 

Step-by-step explanation:

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