1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Goshia [24]
3 years ago
13

Plz need help. is very urgent.

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

Its blurry can you take it again

Step-by-step explanation:

You might be interested in
julio bisects angle PQR and labels a point on the bisector as S. He measures angle PQS with a protractor. The measure of angle P
Paha777 [63]

Answer:

The measure of angle PQR is 74 degrees

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- Bisect an angle means divide the angle into two equal parts in

  measures

- Ex: If angle ABC is bisected by a ray BD then:

- Angle ABC is divided into two equal parts in measure

 m∠ABD = m∠CBD and

 m∠ABC = m∠ABD + m∠CBD

- So we can say measure of angle ABC is twice measure of angle

 ABD or twice measure of angle CBD

*<em> Lets solve the problem</em>

- Julio bisects angle PQR and labels a point on the bisector as S

∴ m∠PQS = m∠RQS

∴ m∠PQR = m∠PQS + m∠RQS

∴ m∠PQR = 2 m∠PQS ⇒ (or 2 m∠RQS)

- He measures angle PQS with a protractor and find its measure is

  37 degrees

∵ m∠PQS = 37°

∴ m∠PQR = 2 × m∠PQS

∴ m∠PQR = 2 × 37 = 74°

∴ The measure of angle PQR is 74 degrees

8 0
3 years ago
Can I get help please! I need it right NOW
Luda [366]
6/7 because it’s a smaller fraction with more pieces. Brainliest???
5 0
3 years ago
1.In what ways did Egypt prosper during the reign of Hatshepsut? do your thing brainly!
Bond [772]

Answer:

She served as a queen, for Thutmose ll.

She served as queen alongside her husband, Thutmose II, but after his death, she claimed the role of pharaoh!. She reigned peace, she built temples and monuments, resulting in the flourishing of Egypt!

srry if this didn't help but I hope it did!

6 0
2 years ago
The average hourly charge of plumbers in the Denver area is $84.00 with a standard deviation of $4.00. Assume that the hourly ch
Simora [160]

Answer:

The probability is 0.31

Step-by-step explanation:

In this question, we are tasked with calculating the probability that a random plumber called at Denver will charge an amount greater than $86 given the mean and the standard deviation.

Firstly, we calculate the standard score of $86 using the mean and the standard deviation.

Mathematically;

z-score = (x-mean)/SD

where x = 86, mean = 84 and SD = 4

z-score = (86-84)/4 = 2/4 = 0.5

Hence, we want to calculate P(z ≥ 0.5)

Using standard table

P( (z ≥ 0.5) = 1 - P(z ≤ 0.5) = 1 - ( 0.19146 + 0.5) = 0.30854

To the nearest hundredth = 0.31

5 0
3 years ago
Can someone help me
Deffense [45]

Answer:

w = 10 cm

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} base × height

here base = 6 and height = 8, thus

A = 0.5 × 6 × 8 = 3 × 8 = 24 cm²

The area of the rectangle = 5 × 24 = 120 cm²

area of rectangle = lw ( l is length, w is width )

Here l = 12, thus

120 = 12w ( divide both sides by 12 )

w = 10 cm

8 0
3 years ago
Other questions:
  • CB clothing ordered sweaters at a wholesale cost of $20 each. The store marked up the price by 50% above the wholesale cost to u
    10·1 answer
  • PLEASE HELP I NEED HELPPP.
    11·1 answer
  • (2x^2 -27)=(3x^2 -6x)
    11·1 answer
  • One math problem. Having trouble, could somebody help
    6·1 answer
  • Solve for x.<br>X-2x-24 = 0<br>A.-4,-6<br>B. -4,6<br>her<br>C. 2-6<br>D. 4,6​
    8·1 answer
  • How do you solve 4x+5y=20?​
    5·1 answer
  • Choose the equation that is equivalent to this statement:
    9·1 answer
  • For what value of k, the following pair of linear equations has unique solution
    8·1 answer
  • Arrange the fractions from the largest to the smallest.
    12·1 answer
  • What number is 40% of 720
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!