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Mandarinka [93]
2 years ago
10

A baseball "diamond" actually forms a square, each side measuring 30 yards. How far, to the nearest yard, must the third baseman

throw the ball to reach first base?
Mathematics
1 answer:
Drupady [299]2 years ago
6 0

Answer:                                                      

15 yards

Step-by-step explanation:

the pitcher is in the middle of the diamond square thingy,the length is 30, so half of 30 is 15

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Answer:

10

Step-by-step explanation:

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3 years ago
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You are traveling at 75 miles per hour on a straight stretch of highway in Nevada. It is noon now. When will you arrive at the n
Levart [38]
Right now it is noon..... you are traveling 75 miles per hour meaning you'll move 75 miles... every hour. so you're 120 miles away so now we need to figure out the time.... to do this we already know 1 hour is 75 miles so now you can subtract one hour 120-75= 45 so 75 per hour, what would 45 be?..... so we can set up a fraction to figure out how long it takes to travel one minute.... so 60/75(the 60 is for minutes in an hour). which is .8 of a second to travel one mile so.... now you can multiply to check your work. .8*75=60 mins.... so now multiply.8*45(miles left)=36 so you'd get there at 1:36 it would take an hour and 36 mins to get to your destination going 75mph
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3 years ago
Suppose a baseball is thrown vertically upward from the ground with an initial velocity of Subscript[v, 0] ft/s. Its height abov
Zina [86]

Answer:

90.5

Step-by-step explanation:

Velocity is a time-derivative of displacement or the height, in this case.

s(t)=-16t^2+v_0t

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At maximum height, the velocity is 0 and the height is 128.

Substitute these values into both equations above,

0 = -32t+v_0

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From the first equation,

128 = -16t^2 + v_0t

Substitute for t.

128 = -16(\dfrac{v_0}{32})^2 + v_0\times\dfrac{v_0}{32}

128 = -v_0^2/64 + v_0^2/32

128=\dfrac{v_0^2}{64}

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4 years ago
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Evgesh-ka [11]
B

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