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Aleksandr [31]
2 years ago
6

A cyclist is riding from the city to the country. She rides 20 miles each hour. At the beginning of the 1 st hour, she is 10 mil

es away from the city center. At the beginning of the 2nd hour, she is 30 miles away from the city center. Write an explicit formula to show her distance from the city at any given hour. Then use the formula to find her distance at the beginning of the 5th hour. ​
Mathematics
1 answer:
strojnjashka [21]2 years ago
7 0

Answer:

450miles

Step-by-step explanation:

Because she is riding at 20 miles per houre means that she ride 450 miles in 5 houre.

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Write an equation in point-slope form and slope-intercept form
liq [111]

Answer:

point-slope form: y - 1 = -4/5(x - 8)    

slope-intercept form:  y = -4/5x + 7.4

Step-by-step explanation:

Find slope using the points (8, 1) and (-2, 9):

  m = (y₂ - y₁) / (x₂ - x₁)

      = (9 - 1) / (-2 - 8)

      = 8 / -10

  m = -4/5

Find y-intercept using slope m from above and anyone of the given points, let's use (8, 1):

  y = mx + b

  1 = -4/5(8) + b

  1 = -6.4 + b

   b = 7.4

Use slope m and y-intercept b above to form equation of line in slope-intercept form:

  y = mx + b

  y = -4/5x + 7.4

For point slope form use slope m from above and a point, again let's use (8, 1):

  y - y₁ = m(x - x₁)

  y - 1 = -4/5(x - 8)    

6 0
3 years ago
HURRY PLEASEEEEEEEEEEE. A coordinate plane. The point (5, 5) is in Quadrant . The point (3, –2) is in Quadrant . The point (–4,
iVinArrow [24]

Answer:

point (5, 5) is in Quadrant: I  (1)

point (3, –2) is in Quadrant: IV   (4)

The point (–4, –4) is in Quadrant: III   (3)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
Write the equation in standard form of the circle with radius 5 and center 0,3
EleoNora [17]
The equation of a circle is (x-h)²+(y-k)²=r², with h being the x value in the center, k being the y value, and r being the radius. x and y can stay variables, so we can plug numbers in to get (x-0)²+(y-3)²=5²=25=x²+(y-3)²
4 0
3 years ago
3.15x4.12=<br><img src="https://tex.z-dn.net/?f=3.15x4.12%20%3D%20" id="TexFormula1" title="3.15x4.12 = " alt="3.15x4.12 = " ali
gulaghasi [49]

Answer:

1/61.8 its right valu of x

Step-by-step explanation:

here we find the first valu and second is also same but there isx so cross the eqal side and get same answer

4 0
3 years ago
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