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katrin2010 [14]

3 years ago

8

mark an fred had some money in the ratio 6:1. mark gave half of his money to fred . what is the ratio of the amount of money mar

k had left to the amount mark had let to the amount of money fred had left

1 answer:

kifflom [539]3 years ago

6 0

The answer I believe is 3:4 but I'm not for sure

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Anyone got the answer?(^•^)

malfutka [58]

Answer:

It's 8

Step-by-step explanation:

$16 ^{ \frac{3}{4} } = \sqrt[4]{16 ^{3} } = \sqrt[4]{2 ^{4 \times 3} } = 2^{ \frac{12}{4} } = 2^{3} = 8$

3 0

2 years ago

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What is the range of the function shown on the graph above?

nikklg [1K]

Answer:

D: 0 < y < 7

Step-by-step explanation:

The domain is the input (i.e. the x values)

The range is the output (i.e. the y values)

So for the range, look at the y-coordinates of the end points of the line: (-6, 0) and (9, 7) ⇒ 0 < y < 7

4 0

2 years ago

Algebra, im so confused

kramer

By analyzing and understanding the graph of the absolute value function, we find that the function evaluated at the x-value equal to 1 is equal to the y-value equal to 3.

<h3>What is the y-value associated to a given x-value of an absolute value function? </h3>

In this problem we find the representation of an absolute value function, where the horizontal axis corresponds to the values of the domain, whereas the vertical axis is for the values of the range. In that picture we must look up for the y-value associated with a given x-value.

Then, we proceed to evaluate the absolute value function at x = 1. In accordance with the graph, the y-value , that is, from the vertical axis, associated with the x-value, that is, from the horizontal axis, equal to 1 is equal to a value of 3.

To learn more on absolute values: brainly.com/question/1301718

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8 0

1 year ago

If x>2, then x^2-x-6/x^2-4=

Viefleur [7K]

Consider the expression $\frac{x^{2} -x-6}{ x^{2} -4}$

To factorize the expression in the denominator we use difference of squares: $x^{2} -4=x^{2} - 2^{2} =(x-2)(x+2)$

To factorize $x^{2} -x-6$ we use the following method:

$x^{2} -x-6=(x-a)(x-b)$

where a, b are 2 numbers such that a+b= -1, the coefficient of x,

and a*b= -6, the constant.

such 2 numbers can be easily checked to be -3 and 2

(-3*2=6, -3+2=-1)

So $x^{2} -x-6=(x-a)(x-b)=(x+3)(x-2)$

$
 \frac{x^{2} -x-6}{ x^{2} -4}= \frac{(x+3)(x-2)}{(x-2)(x+2)}= \frac{x+3}{x+2}$

$\frac{x+3}{x+2}= \frac{x+2+1}{x+2}= \frac{x+2}{x+2}+ \frac{1}{x+2}=1+ \frac{1}{x+2}$

for x>2

$\frac{1}{x+2}\ \textless \ \frac{1}{2+2}= \frac{1}{4}$

thus

for x>2,

$1+ \frac{1}{x+2}\ \textless \ 1+ \frac{1}{4}= \frac{5}{4}$

Answer:

for x>2

$\frac{x^{2} -x-6}{ x^{2} -4} = \frac{x+3}{x+2} \ \textless \ \frac{5}{4}$ , (but the expression is never 0)

8 0

3 years ago

Wat is the answer for 91²×14=

svet-max [94.6K]

Answer:

115934

Step-by-step explanation:

calculator

8 0

3 years ago

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