Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
Answer:
-4x^2+5x-28
Step-by-step explanation:
Expand -7(x^2 +4) = 3x^2+5x-7x^2-28
Simplify 3x^2+5x-7x^2-28 = -4x^2+5x-28
Answer:
Step-by-step explanation:
2,9,6, 2, 3
