Since, the relative frequency is incorrectly mentioned in the question. The correct relative frequency table is attached below.
Answer:
20.
Explanation:
The genotype with the least recombinant frequency will represent the double cross overs.
The double cross overs progeny are a+ b+ c-(2%) and a- b-c+(2%).
The percentage of the recombinant frequency determined the distance between the genes. In the double crossovers, the b gene gas been exchanged and present in the middle.
The single recombinant crossovers as compared with the parents are a+ b+ c+ (8%) and a-b-c-(8%).
Distance between the gene a and b = Single cross overs + double cross overs
Distance between the gene a and b = 8 + 8 +2 +2 = 20.
Therefore, the distance distance between the gene a and b is 20 centi morgan.
Cyanobacteria is the main evidence of life intheearly universe.
Answer:
misalignment of the chromosomes during anaphase II
Abiotic is contain nonliving or abiotic parts. the very bottom one is biome. this is made up of Community. the very top one is ecosystem. and the last one is population. heres your answers.
It will be half
A normal cell contains 46 chromosomes.
Gametes only contain 23 because they will be paired with an opposite gamete cell upon fertilisation
- Egg contains 23
- Sperm contains 23
Together they make the normal amount of 46
