2 years ago

Whoever gets it right and first get Brainlest

Mathematics

2 answers:

Musya8 [376]2 years ago

6 0

Answer:

-5.44

Step-by-step explanation:

Ivenika [448]2 years ago

5 0

Answer:

The answer is -5.44

You might be interested in

Please pe please please please please please help me

BARSIC [14]

Answer:

y =mx

Step-by-step explanation:

The second one is for the gradient

The third one is pythogras theorm

The last one is for the slope of a line(i'm not that sure about this one, sorry if its wrong)

6 0

2 years ago

Using 4 equal-width intervals, show that the trapezoidal rule is the average of the upper and lower sum estimates for the integr

prisoha [69]

Split up the interval [0, 2] into 4 subintervals, so that

$[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]$

Each subinterval has width $\dfrac{2-0}4=\dfrac12$ . The area of the trapezoid constructed on each subinterval is $\dfrac{f(x_i)+f(x_{i+1})}4$ , i.e. the average of the values of $x^2$ at both endpoints of the subinterval times 1/2 over each subinterval $[x_i,x_{i+1}]$ .

So,

$\displaystyle\int_0^2x^2\,\mathrm dx\approx\dfrac{0^2+\left(\frac12\right)^2}4+\dfrac{\left(\frac12\right)^2+1^2}4+\dfrac{1^2+\left(\frac32\right)^2}4+\dfrac{\left(\frac32\right)^2+2^2}4$