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Leona [35]
3 years ago
5

Whoever gets it right and first get Brainlest

Mathematics
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

-5.44

Step-by-step explanation:

Ivenika [448]3 years ago
5 0

Answer:

The answer is -5.44

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What is the common difference between the elements of the arithmetic sequence below?
daser333 [38]
-4.5 might be the answer im not very sure but yeah
5 0
4 years ago
Read 2 more answers
I need help for this
Leona [35]
Got you
S' = 4,-3
Y'= 7,-2
U' = 8,--5
V' = 2,-6

3 0
3 years ago
–10p = –11p − 15<br> What is the answer
tensa zangetsu [6.8K]

Answer: p = −15

Step-by-step explanation:

Add 11p to both sides.

−10p+11p=−11p−15+11p

p=−15

4 0
3 years ago
Read 2 more answers
How do I solve
Maslowich

Use:\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^n\cdot a^m=a^{n+m}\\\\\sqrt[n]{a}=a^\frac{1}{n}\\------------------------\\\\\left(16n^4\right)^{\frac{5}{4}}=16^\frac{5}{4}\left(n^4\right)^\frac{5}{4}=16^{1\frac{1}{4}}n^{4\cdot\frac{5}{4}}=16^{1+\frac{1}{4}}n^5=16^1\cdot16^\frac{1}{4}\cdot n^5\\\\=16\cdot\sqrt[4]{16}\cdot n^5=16\cdot2\cdot n^5=\boxed{32n^5}\\\\\sqrt[4]{16}=2\ because\ 2^4=16\\\\\text{Answer}\ \boxed{\left(16n^4\right)^\frac{5}{4}=32n^5}

4 0
3 years ago
9 to the power 18 = 27 to the power x work out the value of x
Strike441 [17]

Answer:

Step-by-step explanation:

27^x = 9÷(3^x)

So (3^3)^x = (3^2)÷(3^x)

So 3^3x = 3^(2-x)

Comparing powers on both sides,

3x = 2 - x

So, 4x = 2

So, x = 1/2

Given ( 27 ) ^ x = 9 / 3 ^x

⇒ ( 3 × 3 × 3 )^x = ( 3 × 3 ) / 3^x

⇒ ( 3 ³ )^x = 3² / 3^x

⇒  3 ^ 3x × 3^x = 3²            [ since  ( a ^m)^n = a ^mn ]

⇒ 3^ (3x +x) = 3²                [ since a^m × a^n = a ^m+n ]

⇒ 3^4x = 3²

⇒4x = 2                      [ since  If a ^m = a ^n then m = n ]

⇒ x = 2 / 4

 ∴ x = 1 / 2

I hope this helps you.

8 0
3 years ago
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