Given:
Universal set is all positive integers {1,2,3...}
Set A is the set of all positive <u>ODD</u> integers {1,3,5,7...}
The question asks us to find , which is the <em>complement of set A</em>. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.
It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.
ANSWER: "{x|x ∈ U and is an even positive integer}"
You'll find it easier to understand if you illustrate the problem as what is shown in the attached picture. From the illustration and the problem description, two equations can be formulated:
HJ = 2JK
HJ + JK = HK
2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26
That is 4 plus 36x. hope it helps
Answer:
12.5%
Step-by-step explanation:
is the right anwser