1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
I got 0.999 which is 999/1000
Answer:
The discriminant is −4, so the equation has no real solutions.
Step-by-step explanation:
In the equation 0 = x² - 4x + 5, a is 1, b is -4, and c is 5.
Plug in these values into b² - 4ac, and simplify:
b² - 4ac
(-4)² - 4(1)(5)
16 - 20
= -4
So, the discriminant is -4. This means that the equation has no real solutions, because the discriminant is a negative number.
The correct answer is that The discriminant is −4, so the equation has no real solutions.
I think it’s B because 0.25x4=1 L/S
Answer:
To use the coordinate plane to help you find the perimeter and area of various shapes, you first draw the shape on the coordinate plane and then you count the number of unit squares the shape takes up. For the perimeter, it's the number of unit squares that go around the shape.
