initial speed of the racer is given as
after applied force the final speed is given as
now during this speed change the racer will cover total distance 185 m
so here we will use kinematics
now the force that chute will exert on the racer will be given as
B) here following is the strategy for solving it
1. first we used kinematics to find the acceleration of the car
2. then we used Newton's II law (F = ma) to find the force
Answer:
Mass of the pull is 77 kg
Explanation:
Here we have for
Since the rope moves along with pulley, we have
For the first block we have
T₁ - m₁g = -m₁a = -m₁g/4
T₁ = 3/4(m₁g) = 323.4 N
Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have
T₂ - m₂g = m₂a = m₂g/4
T₂ = 5/4(m₂g) = 134.75 N
T₂r - T₁r = I·∝ = 0.5·M·r²(-α/r)
∴ 
Mass of the pull = 77 kg.
If Equal distance is traveled in equal interval of time then it is known as uniform motion in which velocity of object will remain same.
Then if distance covered will be same and the time taken to cover same distance is decreasing then it shows that speed is increasing with time due to which it took less time to cover same distance. This is also known as positive acceleration.
Now if the distance covered will be same and time taken to cover same distance is increasing then it shows that speed is decreasing with time due to which it took more time to cover the same distance. This is also known as negative acceleration.
Now in the above case it is given that the first mile takes you 10 minutes. The second mile takes you 20 minutes. So the time taken is increasing while we cover same distance so this is an example of <u>Negative Acceleration</u>
Answer:
-0.8 m/s²
Explanation:
Acceleration is the slope of a velocity vs. time graph.
a = Δv / Δt
a = (0 m/s − 12 m/s) / (15 s − 0 s)
a = -0.8 m/s²
