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geniusboy [140]
3 years ago
8

Which of the following statements is the best definition of climate?

Physics
1 answer:
noname [10]3 years ago
4 0
Climate is a particular place's distance from the equator
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Distinguish the difference in mass and weight
levacccp [35]
Ok to distinguish the difference you just find out why there's science lol.......anyways.....Mass is the amount of space being taken up in a certain place (or possibly all the world) and weight is the heaviness of an person or thing kk??? also if my answer was best, plzz give brainliest (trust me i need it) Have a great day and Christmas (if u celebrate it)!!
3 0
2 years ago
Hi, can anyone write 5 or 4 paragraph about virus pls I rly need it DO NOT PLAGIARIZE!
Licemer1 [7]
Viruses are microscopic organisms that exist almost everywhere on earth. They can infect animals, plants, fungi, and even bacteria.

Sometimes a virus can cause a disease so deadly that it is fatal. Other viral infections trigger no noticeable reaction.

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4 0
2 years ago
A bystander observes the musicians heading toward each other. When musician #1 is 100 m away, the intensity is 1.24 x 10-8 W/m^2
777dan777 [17]

Explanation:

Given that,

Distance 1, r = 100 m

Intensity, I_1=1.24\times 10^{-8}\ W/m^2

If distance 2, r' = 25 m

We need to find the intensity and the intensity level at 25 meters. Intensity and a distance r is given by :

I=\dfrac{P}{4\pi r^2}.........(1)

Let I' is the intensity at r'. So,

I'=\dfrac{P}{4\pi r'^2}............(2)

From equation (1) and (2) :

I'=\dfrac{Ir}{r'^2}

I'=\dfrac{1.24\times 10^{-8}\times 100}{25^2}

I'=1.98\times 10^{-9}\ W/m^2

Intensity level is given by :

dB=10\ log(\dfrac{I'}{I_o}), I_o=10^{-12}\ W/m^2

dB=10\ log(\dfrac{1.98\times 10^{-9}}{10^{-12}})

dB = 32.96 dB

Hence, this is the required solution.

7 0
3 years ago
Rocks from volcanoes are used by scientists to study the interior of the earth<br><br>TRUE OR FALSE​
cupoosta [38]
I think it’s false bc A volcano is not in the interior of the earth
6 0
3 years ago
Read 2 more answers
A 45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦
Neko [114]

Answer:

v = 21.03 m/s

Explanation:

given,

mass of skier = 45 kg        

the slope of the snow = 10.0◦      

coefficient of friction = 0.114  

distance traveled = 300 m      

speed = ?              

Acceleration = g sin θ - µ g Cos θ        

= 9.8 × Sin (10°) - 0.10 × 9.8 × Cos(10°)        

= 0.737 m/s²      

using equation of motion        

v² = u² + 2 a s        

v² = 0 + 2 × 0.737 × 300            

v = 21.03 m/s                  

Speed of skier's after travelling 300 m speed is  equal to 21.03 m/s

6 0
3 years ago
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