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3 years ago

The rate at which energy is transferred is called

Physics

2 answers:

shusha [124]3 years ago

7 0

Answer:

your answer is power..

makvit [3.9K]3 years ago

6 0

Answer:

The rate at which energy is transferred is called power and the amount of energy that is usefully transferred is called efficiency.

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Although it shouldn’t have happened, on a dive i fail to watch my spg and run out of air. if my buddy is close by, my best optio

leva [86]

Answer:

B ) Ascend using my buddy alternative air source / make an emergency Ascent

Explanation:

From the description it can be seen his buddy is close by of which he can easily use the alternative air source. Also we can see that he is closer to the water surface than his buddy, of which controlled emergency swimming ascent is highly favourable in this condition.

5 0

3 years ago

Read 2 more answers

A 200-gram liquid sample of Alcohol Y is prepared at -6°C. The sample is then added to 400 g of water at 20°C in a sealed styrof

Vinil7 [7]

The specific heat capacity of the alcohol will be 3.72 kJ/kg°C.

<h3>What is the specific heat capacity?</h3>

The amount of heat required to increase a substance's temperature by one degree Celsius is known as its "specific heat capacity."

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

Given data;

Mass of liquid sample of Alcohol m₁ = 200-gram

The temperature of alcohol, T₁ = -6°C.

Mass of liquid sample of water m₂ = 400-gram

The temperature of the water, T₂= 20°C.

The specific heat capacity of the alcohol, S₁=?

The specific heat capacity of water is, S₂=4.19 kJ/kg.°C

As we know that;

<h3 />

$\rm Q_{gain}= Q{loss} \\\\ Q_{alcohol} =Q_{water} \\\\\ m_1s_1\triangle T_1 = m_2S_2 \triangle S_2 \\\\ 200 \times 10^{-3} \times S_1 [ (12-(-6) ] = 40 \times 10^{-3} \times 4.19 \times 10^{-3} \times (20-12)\\\\S_1 = 2 \times 4.19 \times 10^3 \times \frac {8}{18} \\\\ S_1 = 3.72 \ kJ /kg ^0 C$

Hence the specific heat capacity of the alcohol will be 3.72 kJ/kg°C.

To learn more about the specific heat capacity, refer to the link brainly.com/question/2530523.

#SPJ1

6 0

2 years ago

People have proposed driving motors with the earth's magnetic field. This is possible in principle, but the small field means th

fiasKO [112]

Answer:

636.619772368 A

Explanation:

$\tau$ = Torque = $1\times 10^{-3}\ N/m$

B = Magnetic field of Earth = $5\times 10^{-5}\ T$

A = Area

d = Diameter = 20 cm

Current is given by

$I=\dfrac{\tau}{BA}\\\Rightarrow I=\dfrac{1\times 10^{-3}}{5\times 10^{-5}\times \dfrac{\pi}{4}\times 0.2^2}\\\Rightarrow I=636.619772368\ A$

The current is 636.619772368 A

8 0

3 years ago

If a car has a kinetic energy of 40000 J and is moving at a velocity of 25 m/s, what is the mass of the car? KE=1/2mv

ohaa [14]

Answer:

3200 Kg

Explanation:

Just apply the formula:

40.000 = 1/2 . m . 25

80.000 = 25m

m = 80.000/25

m = 3200 Kg

7 0

2 years ago

A heavy-duty stapling gun uses a 0.131-kg metal rod that rams against the staple to eject it. The rod is pushed by a stiff sprin

azamat

Answer:

v = 15.3 m/s

Explanation:

Given:

- The mass of the metal rod m = 0.131 kg

- The spring constant of spring k = 35666 N / m

- The initial compression of the spring x_i = 3.2 ✕ 10^-2m

- The final compression of the spring x_f = 1.3 ✕ 10^-2m

Find:

Find the speed of the ram at the instant of contact.

Solution:

- The ram is initially at rest hence its initial velocity is zero. From conservation of energy principle we have and exchange of gravitational potential and elastic potential energy stored in the spring at initial and final state points:

0.5*m*v^2 + 0.5*k*x_2^2 + m*g*h_f= 0.5*k*x_1^2 + m*g*h_o

m*v^2 + k*x_2^2 + 2m*g*h_f = k*x_1^2 + 2*m*g*h_o

m*v^2 = k*x_1^2 - k*x_2^2 + 2*m*g*(h_o - h_f)

v^2 = k/m*[x_1^2 - x_2^2] + 2*g*(h_o - h_f)

v = sqrt { k/m*[x_1^2 - x_2^2] + 2*g*(h_o - h_f) }

- Where, h_o: is the initial potential energy at compression state x_1.

h_f : is the initial potential energy at compression state x_2

- Plug in the values:

v = sqrt { 35666/.131*[0.032^2 - 0.013^2] + 2*g*(0.032 - 0.013) }

v = sqrt { 232.7819 + 0.37278 } = sqrt { 233.1568 }

v = 15.3 m/s

3 0

3 years ago