Answer: D (doubled)
According to ohm's law
I = V/R ,
V = IR ; R = constant and V is doubled
From the equation
V is directly proportional to the current, and it is given that R is constant ;
2V = 2I. R since R = constant
Hence I is doubled.
Explanation:
The electric force between charges is given by the formula as follows :

k is electrostatic constant
r is distance between charges
Here, charges are equal and opposite. So,

It is clear the force is inversely proportional to the distance between charges and directly proportional to the product of charges. So, greatest force will be providing by :
- Increasing the magnitude of charges
- Decreasing the distance between charges.
The frequency of oscillation on the frictionless floor is 28 Hz.
<h3>
Frequency of the simple harmonic motion</h3>
The frequency of the oscillation is calculated as follows;
f = (1/2π)(√k/m)
where;
- k is the spring constant
- m is mass of the block
f = (1/2π)(√7580/0.245)
f = 28 Hz
Thus, the frequency of oscillation on the frictionless floor is 28 Hz.
Learn more about frequency here: brainly.com/question/10728818
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Among the choices above, the one
that is most closely related to an activated complex is the transition state. The
answer is letter D. This formation forms quickly and does not stay in a way
compound is. It usually forms during the enzyme – substrate reaction.
Answer:
F = -49.1 10³ N
Explanation:
Let's use the kinematics to find the acceleration the acceleration of the bullet that they tell us is constant
² = v₀² + 2 a x
Since the bullet is at rest, the final speed is zero
x = 11.00 cm (1 m / 100 cm) = 0.110 m
0 = v₀² + 2 a x
a = -v₀² / 2 x
a = -1320²/(2 0.110)
a = -7.92 10⁶ m / s²
With Newton's second law we find the force
F = m a
F = 6.20 10⁻³ (-7.92 10⁶)
F = -49.1 10³ N
The sign means that it is the force that the tree exerts to stop the bullet