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Damm [24]
3 years ago
5

How does the euglena differ from the paramecium? Question 20 options: Euglena are photosynthetic. Paramecia use flagella to move

. Paramecia have an "eye spot" to detect light. Euglena have both a macronucleus and a micronucleus
Physics
1 answer:
Sedbober [7]3 years ago
3 0

Answer: Euglena are photosynthetic

Explanation: USA test prep

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Predict the energy transformation that occurs when carson sands a piece of wood with sandpaper.
tigry1 [53]

Answer:

Explanation:

The hand provides Kinetic Energy in moving.

The KE is transformed to Frictional energy

The Frictional Energy can produce heat and light energy.

The sandpaper produces little shreds from the grit of the paper.

The shreds have KE (they move)

6 0
2 years ago
A poker is a long thin tool used to move pieces of coal or logs burning in a fire. To be as safe as possible, the poker should b
nata0808 [166]

Answer:

See the answer below

Explanation:

A poker that will effectively and safely function to move pieces of coal or logs in a burning fire must be fireproof itself. Hence, to be as safe as possible, such <u>poker should be made from a material that is fireproof</u> and that does not conduct a lot of heat. Otherwise, the poker will catch fire/becomes too hot during the course of usage.

3 0
2 years ago
What is the net force on a 50-newton weight hanging on a string tied to the ceiling?
Lady bird [3.3K]
The net force on the hanging object is zero. If it were not zero, then the object would be accelerating in some direction.
4 0
3 years ago
How does a single fixed pulley, like the one seen here, help you do work?
AlexFokin [52]
The correct answer is A.
3 0
3 years ago
Read 2 more answers
A block of ice of mass 4.30 kg is placed against a horizontal spring that has a force constant k = 250 N/m and is compressed a d
OleMash [197]

Answer:

W = 0.060 J

v_2 = 0.18 m/s

Explanation:

solution:

for the spring:

W = 1/2*k*x_1^2 - 1/2*k*x_2^2

x_1 = -0.025 m and x_2 = 0

W = 1/2*k*x_1^2 = 1/2*(250 N/m)(-0.028m)^2

W = 0.060 J

the work-energy theorem,

W_tot = K_2 - K_1 = ΔK

with K = 1/2*m*v^2

v_2 = √2*W/m

v_2 = 0.18 m/s

8 0
3 years ago
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