Answer:
The density of the box is 0.15 g/cm³
Explanation:
Given;
mass of the box, m = 15 g
dimension of the box, = 10 cm by 5 cm by 2 cm
Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³
The density of the box is given by;
Density = mass / volume
Density = 15 g / 100 cm³
Density = 0.15 g/cm³
Therefore, the density of the box is 0.15 g/cm³
Using conservation of momentum, we can solve for the force that the air bag exerts on the person.
Recall the equation for momentum (p):

We can solve for total momentum, then divide by out time interval. This gets us:
F = 4800N
The answer is 10 millimeters in one <span>centimeter</span>
Answer:
10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)
Explanation:
The velocity of the fish relative to the water when it hits the water surface is equal to the resultant velocity between the fish and the water when it hits it.
The fish drops on the water surface vertically with a vertical velocity v. Nothing was said about the velocity of the water, hence we can safely assume that the velocity if the water in the lake is zero, meaning that it is still. Therefore the relative velocity becomes equal to the velocity v with which the fish strikes the water surface.
We use the first equation of motion for a free-falling body to obtain v as follows;
v = u + gt....................(1)
where g is acceleration due to gravity taken as 9.8m/s/s
It should also be noted that the horizontal and vertical components of the motion are independent of each other, hence we take u = 0 as the fish falls vertically.
To obtain t, we use the second equation of motion as stated;

Given; h = 6.10m.
since u = 0 for the vertical motion; equation (2) can be written as follows;

substituting;

Putting this value of t in equation (1) we obtain the following;
v = 0 + 9.8*1.12
v = 10.93m/s
Answer:
10N right
Explanation:
First, we need to find the base of the triangle to find the force acting on the right of the object.
- We have been given the hypotenuse and we need to find the adjacent, so we are using cos
- SOH, CAH, TOA
- cos(θ) = adjacent ÷ hypotenuse
Next, sub in the values (we don't know the adjacent so i've called it x):
To find x, we need to multiply both sides by 60
Now we know all the forces, we can work out the net force:
- Both of the 40N cancel out because they are opposite forces
- The force on the right of the object is 10N stronger than the force on the left (30N - 20N), so the object would move to the right