Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:
20^2=12^2+x^2
400=144+x^2
x^2=400-144
x^2=256
x=16
Answer:
<em>y = - 0.5 | x - 5 | + 2</em><em> </em>
Step-by-step explanation:
g(x) = |x|
step - shifts right 5 units: g(x + 5) = | x <u><em>- 5</em></u> |
step - shifts up 2 units: g(x + 5) + 2 = | x - 5 | <u><em>+ 2</em></u>
step - reflected: - g(x + 5) + 2 =<em> - </em>| x - 5 | + 2
step - stretched by 0.5: <em>y = - </em><u><em>0.5</em></u><em> | x - 5 | + 2</em>
<em>y = - 0.5 | x - 5 | + 2</em>
Answer: hey im not sure, but i think your supposed to solve 7x-6 and 9+12x. Add these two together and times it by 55. Im not syre if this is right but u could try it.
V= 3.14• 5^2•4
V= 3.14 •25•4
V= 78.5•4
V=314
Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:
V=πr2h
Hope this helps comment below for more questions :)
Answer:
∠ EFG = 83°, ∠ GCE = 97°
Step-by-step explanation:
Since FE and FG are tangents to the circle then
∠ FGC and ∠ FEC are right angles
The sum of the angles in quadrilateral CEFG = 360°
Sum the 4 angles and equate to 360
3x + 11 + 90 + 5x - 23 + 90 = 360, that is
8x + 168 = 360 ( subtract 168 from both sides )
8x = 192 ( divide both sides by 8 )
x = 24
Thus
∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°
∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°
