Option C
Math teacher would need to buy 130 prizes
<em><u>Solution:</u></em>
Given that,
Math teacher currently has 109 students and the box has 88 prizes in it
The math teacher likes to keep at least twice as many prizes in the box as she has students
So, she wants the number of prizes to be twice the number of students
Therefore,
number of prizes = 2 x 109 students
number of prizes = 2 x 109 = 218 prizes
The box has 88 prizes in it
Therefore, number of prizes she would need to buy is:
⇒ 218 - 88 = 130
Thus she would need to buy 130 prizes
Answer:
The answer is the third equation. A = 250*(1 +0.016)^(0.75)
Step-by-step explanation:
Since Javier deposited $250 into an account with annual interest rate, then as the years passes his account will grow in the manner shown below:
account(0) = 250
account(1) = account(0)*(1 + 1.6/100) = account(0)*(1 + 0.016) = account(0)*1.016
account(2) = account(1)*1.016 = account(0)*1.016*1.016 = account(0)*(1.016)²
account(3) = account(2)*1.016 = account(0)*(1.016)²*1.016 = account(0)*(1.016)³
account(n) = account(0)*(1.016)^n
Where n is the number of years, account(0) is the initial amount. In this case only 9 months have passed, so we need to convert this value to years, dividing it by 12, which is 9/12 = 0.75. The initial amount was 250, so the equation is:
A = 250*(1.016)^(0.75)
The answer is the third equation.
Answer:
Step-by-step explanation:
Add 5 to both sides
x = 6
Add 3 to both sides
x = -15 +3
x = -12
A = P + I
2a = a + PTR/100
2a = a + 5aT/100
2a = a(1+T/20)
2=1+T/20
T=20 yrs
Answer:
1/2
Step-by-step explanation:
3/6 = 1/2
