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maksim [4K]
2 years ago
10

Help I don’t understand

Mathematics
1 answer:
Aleksandr [31]2 years ago
6 0
Answer included you’re welcome

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Select the two statements that are true about the equation y+6=−10(x−3).
qwelly [4]

I have taken that test (although I don't see you're statements)

I believe the statements to choose from are:

A.) The slope of the line is −10.

B.) The slope of the line is 3.

C.) One point on the line is (3, 6).

D.) One point on the line is (3,−6)

<u>The answers are:</u>

A.) The slope of the line is -10

D.) One point on the line is (3,-6)

<u>Explanation: </u>

The given equation of line is (1).  The point slope form of a line is  (2)  Where m is the slope of line and (x₁,y₁) are points.  On comparing (1) and (2) we get The slope of given line is -10 and the line passing through the points (3,-6).

6 0
3 years ago
What is 13 nickels combined with 6 dimes?
Setler [38]
125 = 6 dimes = 60 and 13 nickles = 65

60+65= 125

Hope i was the brainliest asnwer.
6 0
3 years ago
Please help quick!!
luda_lava [24]
C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2
7 0
2 years ago
Read 2 more answers
A comic book costs $3.99, including tax. It is marked up 45%.
nalin [4]
10% of 3.99=0.399x4=1.596
1% of 3.99=0.0399x5=0.1995
1.596+0.1995=1.7955
1.8(Rounded)+3.99=5.79
7 0
3 years ago
Read 2 more answers
Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
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