Help I don’t understand

A granola bite contains 27 calories. Most of the calories come from grams of carbohydrates. The rest come from other ingredients

GuDViN [60]

Step-by-step explanation:

Given the expression that modeled the relationship between these quantities (calories from grams of carbohydrate and the rest of the ingredients) as

4c+5 = 27

From the equation, the constant value of 5 represents the calories in grams of the rest of the ingredients present in the bite.

Let us calculate the value of c from the equation

4c+5 = 27

4c + 5- 5 = 27-5

4c = 22

c = 22/4

c = 5.5

This means that the total calories of carbohydrate the granola bite contains is 4(5.5) i.e 21 calories of carbohydrate

<em>Note that 8 cannot be the solution to the equation because for us to eliminate 5 from both sides of the equation, we need to subtract it from both sides not add. If 5 was added to both sides, the value of c would have been (32/4 i.e 8) which would have been wrong.</em>

7 0

2 years ago

3.5,-2,0,-7/3,-6 in order from greatest to least

icang [17]

Answer:

in order from greatest to least:

3.5 0 -2 -7/3 -6

Step-by-step explanation:

5 0

3 years ago

Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.

barxatty [35]

Answer:

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

$\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx$

If $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ , $a = 0$ , $b = b$ and $\bar f = 8$ , then:

$\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8$

$\frac{7}{b}\int\limits^b_0 \, dx + \frac{10}{b} \int\limits^b_0 {x}\, dx - \frac{9}{b} \int\limits^b_0 {x^{2}}\, dx = 8$

$\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8$

$7 + 5\cdot b - 3\cdot b^{2} = 8$

$3\cdot b^{2}-5\cdot b +1 = 0$

The roots of this polynomial are determined by the Quadratic Formula:

$b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

7 0

3 years ago

I need help!!! I know it’s late but I really need help in this math homework

sergejj [24]

Answer:

You will have 21 dollars left

Step-by-step explanation:

7 0

2 years ago

I need the answer ...

solong [7]

Ooh so the directions tell us what we need to find the entire line, which is made up of FH. so just add GH (15) and FG (6) together to find FH. so that is 21. FH=21.

3 0

2 years ago