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kenny6666 [7]
3 years ago
15

canoe rental at howie's canoes costs $5 per hour plus an initial deposit of $15. write an expression for how much it costs to re

nt a canoe for any number of hours
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0
This solution only needs proper understanding of the word problem and identification of variables.
Let x = number of hours rental of the canoe

It costs $5 per hour for a canoe. However, for every rental of one canoe, there is a deposit of $15 regardless.
The expression is then 5x + 15.

This expression will solve how much it costs in total to rent one canoe for x hours.
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Given the linear equation 5x+3y-9=0. Write another linear equation in two variables such that the geometrical representation of
just olya [345]

Answer:5x+3y+1=0

Step-by-step explanation:

Given

The linear equation is 5x+3y-9=0

The other linear equation parallel to the given line can be represented by

5x+3y+c=0

Here, c can take any value . for example c=1, line becomes

\Rightarrow 5x+3y+1=0

8 0
3 years ago
Riley's dentist has an aquarium in his office with the dimensions 16 in. By 8.5 in. By 10.5 in. What is the volume of the aquari
ad-work [718]

Answer:

1428

Step-by-step explanation:

I did 16 times 8.5 times 10.5. Good Luck!

6 0
2 years ago
A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to mo
den301095 [7]

This question is incomplete, the complete question;

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 193 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Fatal Accidents 11 13 22 11 15 29 15 9 13 15 22 18

Step 10 of 10 : State the conclusion of the hypothesis test at the 0.1 level of significance.

Answer: H₀ : The distribution of fatal accidents between each month is same

Step-by-step explanation:

H₀ : The distribution of fatal accidents between each month is same

H₁ : The distribution of fatal accidents between each month is different

Let the los be alpha 0.10

given data ;

       Observed    Expected  

Mon   Freq (Oi)   Freq Ei       (Oi-Ei)^2 /Ei

Jan      11    16.0833        1.606649

Feb      13    16.0833        0.591105

Mar      22    16.0833        2.176598

Apr       11    16.0833        1.606649

May     15    16.0833        0.072971

Jun     29    16.0833        10.373489

Jul     15    16.0833        0.072971

Aug       9    16.0833        3.119603

Sep      13    16.0833        0.591105

Oct      15    16.0833        0.072971

Nov      22    16.0833        2.176598

Dec      18    16.0833       0.228411

Total:   193     93                22.689119

Expected Freq ⇒ 193 / 12 = 16.08333

Test Statistic, x² : 22.6891

Num Categories: 12

Degrees of freedom: 12 - 1 = 11

Critical value X² : 24.725

P-Value: 0.0195

since Chi-square value < Chi-square critical value

and P-value > alpha 0.01 so we accept H₀

Therefore we conclude that the distribution of fatal accidents between each month is same

7 0
3 years ago
Evaluate.<br><br> (1/4)^-2 - (5^0x2) x 1^-1
blondinia [14]

Answer:

  14

Step-by-step explanation:

Arithmetic expressions are best evaluated using a reliable calculator. The Google calculator always follows the Order of Operations, so can give you a good answer to such questions.

  (1/4)^-2 - (5^0)(2)(1^-1)

  = 16 - (1)(2)(1) . . . . evaluate the exponents first

  = 16 -2 . . . . . . . . . evaluate the product next

  = 14 . . . . . . . . . . . finally, evaluate the sum

___

The rule of exponents is ...

  a^-b = 1/(a^b)

4 0
3 years ago
Jackson has saved $174.
Inessa [10]

Answer:

15 weeks.

Step-by-step explanation:

5 0
1 year ago
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