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Pepsi [2]
3 years ago
13

A construction company showed that the strength, y, of concrete, measured

Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

  a) y-intercept = 17; initial design strength percentage

  b) slope = 2.8; increase in that percentage each day

  c) 29.6 days to 100% design strength

Step-by-step explanation:

a, b) The equation is in the form called "slope-intercept form."

  y = mx + b

where the slope is m, and the y-intercept is b.

Your equation has a slope of 2.8 and a y-intercept of 17.

The y-intercept is the percentage of design strength reached 0 days after the concrete is poured. The strength of the concrete when poured is 17% of its design strength.

The slope is the percentage of design strength added each day after the concrete is poured. The concrete increases its strength by 2.8% of its design strength each day after it is poured.

__

c) To find when 100% of design strength is reached, we need to solve for x:

  100 = 2.8x +17

  83 = 2.8x

  83/2.8 = x ≈ 29.6

The concrete will reach 100 percent of its design strength in about 30 days.

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Juliette [100K]

Answer: 5.6 ≤ x ≤ 24.13.

Step-by-step explanation:

Given, The graph of the functionP(x) = -0.74^2 + 22x + 75 . The function models the profits, P, in thousands of dollars for a tech company to manufacture a calculator, where x is the number of calculators produced, in thousands.

In graph , On axis → number of calculators produced

On y-axis →  profit made in thousands of dollars.

From the graph, the curve goes for y > 175 from x = 5.6 to x= 24.13 ( approx)

So, the reasonable constraints for the model 5.6 ≤ x ≤ 24.13.

So, If the company wants to keep its profits at or above $175,000, reasonable constraints for the model 5.6 ≤ x ≤ 24.13.

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3 years ago
What is the meaning of descending​
erastovalidia [21]

Answer:

numbers largest to smallest

Step-by-step explanation:

4 0
2 years ago
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Y_Kistochka [10]

Answer:

Here we have the domain:

D = 0 < x < 1

And we want to find the range in that domain for:

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First, if the function is only increasing in the domain (like in this case) the minimum value in the range will match with the minimum in the domain (and the same for the maximums)

f(0) = 0 is the minimum in the range.

f(1) = 1 is the maximum in the range.

The range is:

0 < y < 1.

2) y = f(x) = 1/x.

In this case the function is strictly decreasing in the domain, then the minimum in the domain coincides with the maximum in the range, and the maximum in the domain coincides with the minimum in the range.

f(0) = 1/0 ---> ∞

f(1) = 1/1

Then the range is:

1 < x.

Notice that we do not have an upper bound.

3) y = f(x) = x^2

This function is strictly increasing, then:

f(0) = 0^2 = 0

f(1) = 1^2 = 1

the range is:

0 < y < 1

4) y = f(x) = x^3

This function is strictly increasing in the interval, then:

f(0) = 0^3 = 0

f(1) = 1^3 = 1

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0 < y < 1.

5) y = f(x) = √x

This function is well defined in the positive reals, and is strictly increasing in our domain, then:

f(0) = √0 = 0

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The range is:

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4 0
3 years ago
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Given.

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Substitute x into the first equation and simplify.

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Invert.

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Substitute Y into your second equation.

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x+2(-3)=0

x-6=0

Add -6 to both sides.

(x-6)+6=0+6

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Answer:

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Is (x + 5) a factor of f(x) = x3 − 4x2 + 3x + 7?
Vaselesa [24]

Answer:

Step-by-step explanation:

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