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Radda [10]
3 years ago
11

WHAT capital letter forms a parallel lines

Mathematics
2 answers:
Inga [223]3 years ago
7 0
The letter H . Because the two lines on the right and left will never cross. Hope it helped. ;)
Nikolay [14]3 years ago
4 0
The lines on the left and right of H are parallel. You know this because the line bisecting the two is perpendicular to both of them.
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_30. Solve the following logarithmic equation: log8(x + 9) + 3 = 3
Bezzdna [24]

Answer:

A

Step-by-step explanation:

using the rule of logarithms

log_{b} x = n ⇒ x = b^{n}

log_{8} (x + 9) + 3 = 3 ( subtract 3 from both sides )

log_{8} (x + 9) = 0 , then

x + 9 = 8^{0} = 1 ( subtract 9 from both sides )

x = - 8

7 0
2 years ago
29/5 divided by nine and a half
trapecia [35]

29/5 is 5.8   5.8 dividen by 9 1/2 is 0.61052631578

Hope this helps! Have a great day!!!

3 0
3 years ago
WORTH 100 POINTS need the answers asap
Lena [83]

<u>Answer:</u>

f(x) = x^2 , x < 2

f(x) = 5, 2\leq x < 4

<u>Step-by-step explanation:</u>

We have a parabola and a small line shown in the graph.

The parabola goes upto x = 2 but does not reach that very value. So x = 2 starts on the line above where x = 2 and ends just before x = 4.

Therefore, this function can be modeled by:

f(x) = x^2 , x < 2

f(x) = 5, 2\leq x < 4

4 0
3 years ago
Read 2 more answers
Factor 5v^2 - 23v - 10​
AfilCa [17]

Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

ac  = -50

The sum of the factors of -50 should add up to -23.

-25 and 2 work for this.

Expand and factor:

  • 5v^2 - 23v - 10
  • 5v^2 - 25v + 2v - 10
  • 5v(v - 5) +2(v -5 )
  • (5v + 2)(v - 5)

The factored expression is (5v + 2)(v - 5)

7 0
2 years ago
If a+b=9 and ab=18,find the value of a and b.
Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

:)

3 0
3 years ago
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