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3 years ago

Question 2 of 10

Mathematics

1 answer:

solong [7]3 years ago

7 0

Answer:

C. $176.000

Step-by-step explanation:

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What is the equation of the line that passes through the point (-5,1) and has a slope of -1/5?

olchik [2.2K]

Answer:

x + 5y = 0

Step-by-step explanation:

y = mx + b

y = -1/5 x + b

1 = -1/5 (-5) + b

1 = 1 + b

b = 0

y = -1/5 x

5y = -x

x + 5y = 0

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Charles needed 3/4 cups of rasins. if he has a 1/4 measuring cup, how many times will he need to fi'll it up to get to the right

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Identify each as an example of exponential growth or decay. What is the y-intercept? What is the end behavior? 1)y=10(0.45)^x 2)

jeyben [28]

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3 years ago

Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –

Maslowich

Answer:

answer is:

$y=x^{3}-10 x,y=x^{2}-6$

Step-by-step explanation:

we are asked to find which system of equations can we use to find the roots of the equation:

$x^{3}-10x=x^{2}-6$

since the system of equation in last part is given as:

$y=x^{3}-10 x,y=x^{2}-6$

so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:

$x^{3}-10x=x^{2}-6$ .

3 0

3 years ago

Read 2 more answers

Given: A, B, and C What is the value of X in the matrix equation AX + B = C?

Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

$A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}$

$B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}$

$C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}$

AX + B = C

AX = C - B

C - B = $\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}$ = $\begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}$

C - B = $\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}$

Let $X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}$

AX = $\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}$

= $\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}$

Since AX = C - B

$\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}$

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = $\begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix}$ will be the answer.

7 0

3 years ago