2 years ago

What is the slope of the line that is perpendicular to the line that goes through the two points (-8, 3) and (4, 27)?

Mathematics

1 answer:

Mademuasel [1]2 years ago

8 0

Answer:

-1/2 or -0.5

negative half

Step-by-step explanation:

slope of regular line= (y1-y2) / (x1-x2)

(27-3) / (4 - -8)

24 / (4+8)

24 / 12 = 2

the slope of a perpendicular line is the negative reciprocal

the negative reciprocal of positive 2/1 (2 as a fraction) is:

negative half: -1/2 or -0.5

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Elimination method<br> 4x-2y=48<br> 2x+6y=-18

yulyashka [42]

$4x-2y=48\\ \\ 2x+6y=-18$

First we'll multiply the second equation by -2

$-2\cdot (2x+6y)=-2\cdot -18\\ \\ -4x-12y=36$

Now let's add the new equation and the first one.

$(4x-2y)+(-4x-12y)=48+36\\ \\ 4x-4x-2y-12y=48+36\\ \\ -14y=84\\ \\ y=\frac { 84 }{ -14 } \\ \\ y=-6$

We found y's value. We'll plug it in one of the equations to find x's value.

$y=-6\\ \\ 4x-2y=48\\ \\ 4x-2\cdot -6=48\\ \\ 4x+12=48\\ \\ 4x=48-12\\ \\ 4x=36\\ \\ x=\frac { 36 }{ 4 } \\ \\ x=9$

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(9, -6)

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3 years ago

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Simplify 2^3 x 2^18

dybincka [34]

Answer:

2^21

Step-by-step explanation:

3+18=21

4 0

2 years ago

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