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yan [13]
3 years ago
12

You have a package of 20 assorted thank-you cards. You pick the four cards shown. How many of the 20 cards would you expect to h

ave flowers on them?

Mathematics
2 answers:
fgiga [73]3 years ago
8 0

Answer:

5 cards

Step-by-step explanation:

There's 20 cards and in 1 group, 4 cards. There are 1 out of 4 cards in each group. If you keep counting, there will be 5 in total, because 4*5=20. Think of it like this: Each period is a card without flowers and each comma is a card with flowers.

..., ..., ..., ..., ...,

Hope this helps!

AlladinOne [14]3 years ago
7 0

Answer:

5 out of 20

Step-by-step explanation:

1 out of four cards have flowers on them which it means you can expect a fourth of the 20 twenty cards to have flowers. 20 divided by 4 is five.

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Please help, will give brainliest!<br>(please explain how as well)​
vovikov84 [41]

Answer:

C

Step-by-step explanation:

Since GJ bisects ∠ FGH , then ∠ FGJ = ∠ JGH = x + 14

∠ FGH = ∠ FGJ + ∠ JGH , substitute values

4x + 16 = x + 14 + x + 14 = 2x + 28 ( subtract 2x from both sides )

2x + 16 = 28 ( subtract 16 from both sides )

2x = 12 ( divide both sides by 2 )

x = 6

Thus

∠ FGJ = x + 14 = 6 + 14 = 20° → C

4 0
3 years ago
What is the answer???
nexus9112 [7]
Try this, I think its correct

y= 4(x- \frac{7}{8})^{2}+ \frac{159}{16}
6 0
3 years ago
Please help me out! And please show your work!!<br> |<br> |<br> |<br> v
Sedaia [141]
8/20 is your answer buddy
6 0
3 years ago
Read 2 more answers
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
Plz help i need to finish this asap so i can graduate
Sloan [31]
F(x) = x^2 + 3x + 2
if g(x) is the reflection of f(x) across the x - axis then
g(x) = -f(x)
g(x) = - (x^2 + 3x + 2)
g(x) = - x^2 - 3x - 2
8 0
3 years ago
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