The value of the digit 3 in 730,500 is the value of the digit 3 in 73,050

Quadrilateral RJFT is similar to quadrilateral SYPA . JF=60 mm , AP=40 mm , and YP=25 mm . What is TF ?

Hoochie [10]

The two quadrilaterals are similar. Which means the ratios of respective sides of two quadrilaterals will be the same.

So, for the given quadrilaterals, ratio of sides JF and TF of quadrilateral RJFT will be equal to the ratio of sides YP and AP of quadrilateral SYPA. Mathematically, we can write:

$JF:TF = YP:AP \\ \\ 
 \frac{JF}{TF} = \frac{YP}{AP} \\ \\ 
 \frac{60}{TF} = \frac{25}{40} \\ \\ 
60* \frac{40}{25}=TF \\ \\ 
TF=96mm$

So the measure of TF will be 96mm

7 0

3 years ago

How many times greater is the value of 4 in 547 than the value of the 4 and 84

sesenic [268]

Answer:

10

Step-by-step explanation:

How many times greater is the value of 4 in 547 than the value of the 4 and 84?

547: 500 + 40 + 7

5 is in the hundreds place

4 is in the tens place

7 is in the ones place

84: 80 + 4

8 is in the tens place

4 is in the ones place

The value of 4 in 547 is 10 times greater than the value of 4 in 84.

Since the 4 in 547 is in the tens place, while the 4 in 84 is in the ones place.

Also, 4 * 10 = 40

Hope this helps!

6 0

3 years ago

Solve 9(a + 2b) + c a = 3 b = 2 c = 1

swat32

Answer:

64

Step-by-step explanation:

Step 1: Define

9(a + 2b) + c

a = 3

b = 2

c = 1

Step 2: Substitute and Evaluate

9(3 + 2(2)) + 1

9(3 + 4) + 1

9(7) + 1

63 + 1

64

4 0

3 years ago

Read 2 more answers

Which equation represents the line that has a slope of 4 and passes through the point (2, 7)?

Wittaler [7]

Answer:

The answer is y = 4x - 1.

Step-by-step explanation:

☆The equation we'll be using: y = mx + b

☆Since we already have the slope. we have to find the y-intercept.

☆ $y = mx + b \\ \\ 7 = 4(2) + b \\ 7 = 8 + b \\ \frac{ - 8 = - 8 \: \: \: \: \: \: \: \: \: \: \: }{ - 1 = b \: \: \: \: \: \: \: \: \: \: }$

☆Using the information we gathered and was given, we just to put them together.

☆ $y = 4x - 1$

3 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

Supposing 60 out of 100 scores are passing scores, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago