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Helen [10]
3 years ago
10

Which ordered pair makes both inequalities true?

Mathematics
2 answers:
Digiron [165]3 years ago
5 0
For a
0 > -3(1) + 3 i.e. 0 > 0 (not true)
For b
1 > -3(-1) + 3 i.e. 1 > 6 (not true)
For c
2 > -3(2) + 3 i.e. 2 > -3 (true)
2 > 2(2) - 2 i.e. 2 > 2 (not true)
For d
3 > -3(0) + 3 i.e. 3 > 3 (not true)

Therefore, none of the ordered pairs makes both inequalities correct.
grigory [225]3 years ago
4 0

Answer:

a. (1,0)

Step-by-step explanation:

In order to calculate this, you just have ot insert the value of X into the inequality to evaluate it and see if it makes both correct, remember that the points are ordered as (x,y).

First enequality:

y=-3x+3\\y=-3(x)+3\\y=0

SO we know that the first one is true, the second one would be:

y=2x-2\\y=2(1)-2\\y=0\\

Now we know that both inequalities are true when evaluated for (1,0)

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<span>Curtis threw 15 darts at a dartboard. 40% of his darts hit the bull's-eye.
Let’s find out how many darts did not hit the bull's-eye.
=> 15 darts = 100%
=> 40% of 15 hits bull’s eye.
Now let’s solve:
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we need to get the 40% value of 15 to know how many darts was able to hit bull’s eye.
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If a sequence is defined recursively by f(0)= 3 and f(n + 1)= -f(n) +5 for n ≥ 0, then f(2) is equal to a) 2 b)3 c)5 d)8
jok3333 [9.3K]
Answer: B) 3

-----------------------------------------------------------

f(0) = 3 is the given initial term
f(n+1) = -f(n)+5 is the recursive rule

Plug in n = 0 to find the next term
f(n+1) = -f(n)+5
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we stop here because we found the value for f(2)

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Nataly_w [17]
Hi there!

The answer to this question is A - multiply by 1/2. This is because multiplying by 1/2 does not get rid of the 1/2 on that side, which is what we want to do.

Hope this helps!! :)
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