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Svetach [21]
3 years ago
14

What is ⅓ (1 third) times three??

Mathematics
2 answers:
Mashutka [201]3 years ago
4 0

Answer:

One!

Step-by-step explanation:

Split a circle into 3 equal parts. Take one. That one part is 1/3 of the circle!

Fractions are essentially division, but when you multiply an integer (whole number) by a fraction, only multiply the number by the numerator (top number). 1x3/3 = 3/3, and 3 divided by 3 equals 1! Hope this helps!

RoseWind [281]3 years ago
3 0

The answer to this problem is one because 1/3 3 times is 3/3 which is equal to one.

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Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.
lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
Approximately how many people make between $30,000 and $66,000​
Alja [10]

Answer:

approximately 1 to 7.674 billion people

Step-by-step explanation:

cause theres 7.674 billion peepsin the world

8 0
3 years ago
2x times 6 help please i need it (saying with bored voice)
Bumek [7]
12. The answer is 12 because two x 6 is twelve awesome
5 0
3 years ago
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
Write the slope-intercept form of the equation of each line 13x-2y=14
HACTEHA [7]

Answer:

Step-by-step explanation:

First, lets put this into y=mx+b form.

You can bring the 13x over to the 14, by subtracting and you get -2y=14-13x, or also -2y = -13x + 14

Then you can divide both sides by -2 to get y, and you get

-2y/-2 = -13x/-2 + 14/-2 which is simplified to y=13/2x + (-7) which is

y=13/2x-7

                                {[( IMPORTANT )]}

 THIS HAS THE SLOPE IN A IMPROPER FRACTION... CHECK IF YOU USE MIXED NUMBERS OR IMPROPER FRACTIONS

the mixed number form is y = 7     1/2 x -7

Hope this helps!

       

7 0
3 years ago
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