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3 years ago

What is ⅓ (1 third) times three??

Mathematics

2 answers:

Mashutka [201]3 years ago

4 0

Answer:

One!

Step-by-step explanation:

Split a circle into 3 equal parts. Take one. That one part is 1/3 of the circle!

Fractions are essentially division, but when you multiply an integer (whole number) by a fraction, only multiply the number by the numerator (top number). 1x3/3 = 3/3, and 3 divided by 3 equals 1! Hope this helps!

RoseWind [281]3 years ago

3 0

The answer to this problem is one because 1/3 3 times is 3/3 which is equal to one.

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A population of n = 7 scores has a mean of m = 10. if one score with a value of x = 4 is removed from the population, what is th

sukhopar [10]

Number of scores n = 7
Mean of the total scores, m = 10
One value is given that is x = 4.
Calculating the total T = m x n = 10 x 7 = 70
Total without the given value = 70 - 4 = 66
Mean of the remaining scores would be 66 / 6 = 11.

4 0

3 years ago

Spencer plants a 7-inch tomato plant in his garden. The plant grows by about 15% per week for several months. Which formula repr

Mnenie [13.5K]

Answer:

$h(t) = 7(1.15)^{t}$

Step-by-step explanation:

The equation for the plant's height after t weeks has the following format:

$h(t) = h(0)(1+r)^{t}$

In which h(0) is the initial height and r is the rate it increases per week, as a decimal.

Spencer plants a 7-inch tomato plant in his garden.

This means that $h(0) = 7$

The plant grows by about 15% per week for several months.

This means that $r = 0.15$ . So

$h(t) = h(0)(1+r)^{t}$

$h(t) = 7(1+0.15)^{t}$

$h(t) = 7(1.15)^{t}$

4 0

3 years ago

Determine the end behavior of each rational function below. <br> f(x) = 7x3 + 2 / 4x5 − 3x + 1

Tems11 [23]

Answer:

When x ⇒ +∞ and x ⇒ -∞, f(x) ⇒ 0 from the positive region.

Step-by-step explanation:

Hi there!

Let´s write the function:

f(x) = (7x³ + 2) / (4x⁵ - 3x + 1)

When x ⇒ +∞ we can neglect the constant values (2 and 1). So:

f(x) ⇒ 7x³ /(4x⁵ - 3x)

f(x) ⇒ 7x³ / x(4x⁴ - 3)

f(x) ⇒ 7x² / 4x⁴

f(x) ⇒ 7/4x² ⇒ 0 from the positive region

when x ⇒ -∞

f(x) ⇒ 7/ 4x² ⇒ 0 from the positive region because x² is always positive.

Then when x is a very big number (positive or negative), f(x) will be approximately 0 and positive.

4 0

3 years ago

Find all points on the x-axis that are 14 units from the point (4, -7).

BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

Distance between two points:

Suppose we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

$\sqrt{(x-4)^2+(0-(-7))^2} = 14$

$\sqrt{x^2 - 8x + 16 + 49} = 14$

$\sqrt{x^2 - 8x + 65} = 14$

$(\sqrt{x^2 - 8x + 65})^2 = 14^2$

$x^2 - 8x + 65 - 196 = 0$

$x^2 - 8x - 131 = 0$

So $a = 1, b = -8, c = -131$

$\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588$

$x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12$

$x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12$

The points are: (16.12,0),(-8.12,0).

4 0

3 years ago

Find the sum of 80/100 and 20/100

ololo11 [35]

We have the same denominator. Therefore:

$\dfrac{80}{100}+\dfrac{20}{100}=\dfrac{80+20}{100}=\dfrac{100}{100}=1$

7 0

3 years ago

Read 2 more answers