Answer:
x = 30 and y = -34
Step-by-step explanation:
Given the following functions
(1/4)^(x+y) = 256... 1
log₄(x-y) = 3.... 2
From equation 2;
x-y = 4³
x-y = 64
x = 64 + y ... 3
Substitutw 3 into 1
From 1:
(1/4)^(x+y) = 256
(1/4)^(64+y+y) = 256
(1/4)^(64+2y) = 256
Take log₄ of both sides
64+2y log₄ (1/4) = log₄256
-(64+2y) = 4log₄4
-(64+2y) = 4
64+2y = -4
2y = -4 - 64
2y = -68
y = -34
Since
x = 64 + y .
x = 64 - 34
x = 30
Hence x = 30 and y = -34
The answer is letter C. symmetric
Answer: -√1/✓41
Step-by-step explanation:
Let y be the irrational number that will be multiplied by -√41 to get the product that equals 1.
y × (-√41) = 1
We then solve for y, by dividing through with -√41. This will be:
[y × (-√41)]/-√41 = 1/-√41
y = -1/√41
y = -√1/✓41
The irrational number is negative root one over root forty one.
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
