Unfortunately, your answer is incorrect, but I totally understand your thinking. However, 1/4 is the probability for each individual that they'll be placed in a general civil case. Since there are two of them, and the question is asking the probability that only one will be in a general civil case, you have to approach the problem slightly differently.
There is a 1/16 chance that both will be put in the case (1/4 * 1/4), a 9/16 chance that neither will be put in the case (3/4 * 3/4), and therefore leaving a 6/16 chance that only one of them will be placed in the civil case. (1 - (1/16 + 9/16). This is equivalent to the decimal 0.375.
Draw out a chart of all the 16 possibilities, and circle the ones where the criteria meet. You'll find that there are 6 instances where one of them is put in a general civil case alone.
Answer:
A) C=6t
Step-by-step explanation:
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Answer:
(x,y) -> (x-6, y+5)
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
We know that point C is in the middle of point A and point B.
That means that when these two equations are added they should be equal to the length of AB which is 41.
5x+3x-7=41
add 7 to both sides
8x=48
divide both sides by 8.
x=6