Graphing exponential functions and then State the domain, range and asymptote
1 answer:
9514 1404 393
Answer:
D: all real numbers
R: f(x) > 0
A: f(x) = 0
(-∞, 0), (+∞, +∞)
vertical stretch by a factor of 2; left shift 2 units
Step-by-step explanation:
The transformation ...
g(x) = a·f(b(x -c)) +d
does the following:
- vertical stretch by a factor of 'a'
- horizontal compression by a factor of 'b'
- translation right by 'c' units
- translation up by 'd' units
For many functions, horizontal coordinate changes are indistinguishable from vertical coordinate changes. Exponential functions tend to be one of those.
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Using the above notation, you seem to have f(x) = 3^x, and g(x) = 2f(x+2). The transformation is a vertical stretch by a factor of 2, and a translation left 2 units.
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As with all exponential functions, ...
- the domain is "all real numbers"
- the range is all numbers above the asymptote: f(x) > 0
- the horizontal asymptote is f(x) = 0
The function is a growth function, so ...
- x → -∞, f(x) → 0
- x → ∞, f(x) → ∞
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<em>Additional comment</em>
The left shift is equivalent to an additional vertical stretch. The function could be rewritten as ...
f(x) = 18(3^x)
with no left shift and a vertical stretch by a factor of 18 instead of 2.
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Answer: The correct option is, The coefficient of the first term.
Step-by-step explanation:
The given function is,
End behavior of the polynomial function : It is defined as the graph of f(x) as x approaches and
.
The end behavior of the graph depends on the leading coefficient and degree of the polynomial.
As, the degree of the polynomial is '3'. So, the leading coefficient will determine the structure of the graph.
Therefore, the coefficient of the first term will indicate that the left end starts at the top of the graph.
The graph is also shown below.
