Answer:
20/3 ounces of water is added.
Step-by-step explanation:
how many ounces of pure water should be added to 20 ounces of 40% solution of muriatic acid to obtain a 30% solution of muriatic acid?
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The acid is 40% of 20 ounces = 8 ounces.
0.4*20 = 8
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That same 8 ounces is to be 30%. The water will be the other 70%.
8/30 = x/100
30x = 800
x = 80/3, the total amount of the solution.
We started with 20, so 80/3 - 20 = 20/3
20/3 ounces of water is added.
Answer:
103&（#！92（$+#”39214849）？lm
Answer:
188.496 mm^3 (or 188.495559 mm^3 if you want to be specific)
Step-by-step explanation:
The radius would be the distance from the middle of the circle on top, we are given that the diameter of the circle is 4mm, the radius is half of that so you would get 2 as the radius (or R). H is the height of the cylinder which is 15 mm, so plugging it in (pi * (2^2) * 15) would get you 188.496 mm^3 (rounded of course).
Hello,
the answer is D (said Al Kashi)
