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Lubov Fominskaja [6]
3 years ago
8

Yasmin swims at a constant rate of 2 km/h for 2.5 h. How far does Yasmin swim? 4.5 km 5 km 6 km 6.5 km

Mathematics
1 answer:
Neporo4naja [7]3 years ago
3 0
She swims for 2.5 hours at a rate of 2 km/hr
Multiply 2.5 * 2 = 5 km
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(cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=?
Tasya [4]
Do you mean <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x+5<span>cos3</span>x+10cosx</span></span>  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x+5cos3x+10cosx</span></span>  ?</span> or <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x</span></span>+5<span>cos3</span>x+10cosx  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x</span></span>+5cos3x+10cosx  <span>?</span></span>
7 0
3 years ago
what are the coordinates of the point on the directed line segment (-1,-2) to (9,-10) that partitions the segment into a ratio o
Ymorist [56]

Answer:

[6.5,-7.25]

Step-by-step explanation:

Given the partitioning ratio as 3:1

#Find the length of the x-coordinate and multiply by the ratio:

x length=9--1=10

=>\frac{1}{4}\times 10=2.5

#We subtract 2.5 from the x-max to get the point=9-2.5=6.5

#Find the length of the y-coordinate and multiply by the ratio:

x length=-9--2=-7

=>\frac{1}{4}\times -7=-1.75

#We subtract -1.75 from the y-max to get the point=-9--1.75=-7.25

Hence,  the coordinates that partitions the segment into a ratio of 3 to 1 is [6.5,-7.25]

4 0
3 years ago
Find the least common denominator. (Enter the denominator only.)<br> 1/2, 5/6
Mama L [17]

Answer:

6

Step-by-step explanation:

2 goes into 6 evenly so two times three equals six so you multiply 1 by three and it gives you 3/6

8 0
4 years ago
Match the numerical expressions to their simplest forms.
Aloiza [94]

Answer:

(a^6b^1^2)^\frac{1}{3} = a^2b^4

\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}} = a^3b^2

(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4} = a^2b

(\frac{a^3}{ab^-^6})^\frac{1}{2} = ab^3

Step-by-step explanation:

Simplify each of the expressions:

1

(a^6b^1^2)^\frac{1}{3}

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

(a^6b^1^2)^\frac{1}{3}

a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}

Simplify,

a^2b^4

2

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}

Rewrite as square roots:

\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}

Simplify,

\sqrt{a^5b^3}*\sqrt{ab}

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

\sqrt{a^5b^3*ab}

Simplify,

\sqrt{a^6b^4}

Since this operation is taking the square root, divide the exponents in half to do this operation:

a^3b^2

3

(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

(\frac{a^8}{b^-^4})^\frac{1}{4}

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

(a^8b^4)^\frac{1}{4}

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

\sqrt[4]{a^8b^4}

SImplify, divide the exponents by (4) to simulate taking the quartic root,

a^2b

4

(\frac{a^3}{ab^-^6})^\frac{1}{2}

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}

(a^2b^6)^\frac{1}{2}

Rewrite to the half-power as a square root,

\sqrt{a^2b^6}

Simplify, divide all of the exponents by (2),

ab^3

7 0
3 years ago
4x-5y=13 10x+2y= 40 help
stepan [7]
14x-3y=53 is the answer. I put one equation over the other since there are two of them that needed to be solved

3 0
3 years ago
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