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fomenos
3 years ago
8

Which is NOT an example of a space figure?

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
The pyramid is not a example of a space figure for this question
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A bag contains 10 black, 15 white, and 25 blue marbles. What is the probability of randomly selecting one
gulaghasi [49]

Answer: 0.8 or 80%

Step-by-step explanation:

First find the total number of marbles:

10 + 15 + 25 = 50 marbles total

To find the number of marbles that are not black:

15 + 25 = 40 marbles that are not black

Set up ratio:

\frac{40}{50} = 0.8 or 80%

4 0
3 years ago
Jamie purchased a condo in Naples, Florida, for $699,000. She put 20% down and financed the rest at
ololo11 [35]

By applying the formulas of present and future values of annuity we can solve this problem. In this mortgage problem, first we have to find loan amount after the down payment. It is 699,000 - 699,000 * 0.2 = 559,200$. We have to set it as PV (Present Value) of annuity. Using the PV formula PV = A \frac{[1- \frac{1}{(1+r)^{N}}]}{r}, we first find A, which is an annual payment. Exact calculation with mortgage calculator gives us A = 33,866.56$. After finding it, plugging this number into FV (Future Value) formula FV = A\frac{[(1+r)^{N}-1]}{r}, we find the value of the future value and it is 1,185,329.66$. And the total financial charge is 1,185,329.66 - 559,200 = 626,129.66$

6 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
1)Circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1)(2, 1) and has a radiu
galina1969 [7]

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = \pi.r^{2}\alpha÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

8 0
3 years ago
HELP ASAP!!!!!!!! IF YOU CAN I WILL GIVE 5 STARS!!!!!!!!!
fiasKO [112]

Answer:

150 units³

Step-by-step explanation:

l * w * h = volume, so...

10*5*3 = volume

150 = volume

3 0
3 years ago
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