2) the center seats of the first three rows are broken. --> 12/2 = 6 --> since 6 is not the exact center, you would have to consider the center seats as seat#6 and seat#7
3) so, that would mean 2broken seats per row --> 3X2 = 6broken seats
4) 96 – 6 = 90
Therefore, there are 90 working seats in that section.
First multiply 12 by 8 to get 96 that is the total amount of seats including the broken ones. then multiply 3 by 4 to get the section of broken seats. 3 being the amount of rows that have broken seats an 4 is the amount of broken seats per row. you wind up with 12 broken seats. Now subtract 12 from 96 to get 84 functional seats
It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.