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navik [9.2K]
3 years ago
13

Need help please

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{-2-(-4)}\implies \cfrac{-1}{-2+4}\implies -\cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=-\cfrac{1}{2}[x-(-4)]\implies y-6=-\cfrac{1}{2}(x+4)

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maksim [4K]

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Find n for the sequence for which a1 = 30, d = -4 and sn= -210.
REY [17]

n\in\mathbb{N^+}

The formula of the sum of an arithmetic sequence:

S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n

We have:

a_1=30;\ d=-4;\ S_n=-210

substitute:

\dfrac{2\cdot30+(n-1)(-4)}{2}\cdot n=-210\ \ \ |\cdot2\\\\(60-4n+4)n=-420\\\\(64-4n)n=-420\\\\64n-4n^2=-420\ \ \ |:(-4)\\\\n^2-16n=105\ \ \ |-105\\\\n^2-16n-105=0\\\\n^2+5n-21n-105=0\\\\n(n+5)-21(n+5)=0\\\\(n+5)(n-21)+0\iff n+5=0\ \vee\ n-21=0\\\\n=-5\notin\mathbb{N^+}\ \vee\ n=21\in\mathbb{N^+}

Answer: b. 21

3 0
4 years ago
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Aleonysh [2.5K]

x+2(x+1)=35

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4 0
3 years ago
G(x) = 9x plug in g(9)​
monitta

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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