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navik [9.2K]
2 years ago
13

Need help please

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
8 0

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{-2-(-4)}\implies \cfrac{-1}{-2+4}\implies -\cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=-\cfrac{1}{2}[x-(-4)]\implies y-6=-\cfrac{1}{2}(x+4)

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ser-zykov [4K]
First, you have to find the equation of the perpendicular bisector of this given line. 
to do that, you need the slope of the perpendicular line and one point.
Step 1: find the slope of the given line segment. We have the two end points (10, 15) and (-20, 5), so the slope is m=(15-5)/(10-(-20))=1/3
the slope of the perpendicular line is the negative reciprocal of the slope of the given line, m=-3/1=-3 
step 2: find the middle point: x=(-20+10)/2=-5, y=(15+5)/2=10      (-5, 10)
so the equation of the perpendicular line in point-slope form is (y-10)=-3(x+5)

now plug in all the given coordinates to the equation to see which pair fits:
(-8, 19): 19-10=9, -3(-8+5)=9, so yes, (-8, 19) is on the perpendicular line. 

try the other pairs, you will find that (1,-8) and (-5, 10) fit the equation too. (-5,10) happens to be the midpoint. 

4 0
2 years ago
Read 2 more answers
Simon pays $9 for 6 visits to swim at the community pool. He pays $18 for 12 visits to swim. How much does it cost for each visi
sergij07 [2.7K]

Answer:

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Step-by-step explanation:

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Hope this helps :)

8 0
2 years ago
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Lelu [443]

Answer: it’s C

Step-by-step explanation:

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2 years ago
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storchak [24]

Answer:

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Step-by-step explanation:

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Vedmedyk [2.9K]

Answer:

A = $ 7,299.92

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A = P(1 + r/n)nt

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A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

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r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

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