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navik [9.2K]
2 years ago
13

Need help please

Mathematics
1 answer:
Morgarella [4.7K]2 years ago
8 0

\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{-2-(-4)}\implies \cfrac{-1}{-2+4}\implies -\cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=-\cfrac{1}{2}[x-(-4)]\implies y-6=-\cfrac{1}{2}(x+4)

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4 0
3 years ago
I kinda need help with this
andreev551 [17]

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x = 1

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f(x) = 3 or y = 3

Locate y = 3 on the y- axis , go horizontally across to meet the line at (1, 3 )

Then

When f(x) = 3 , x = 1

7 0
2 years ago
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