Point slope form is y-(-4) = 1/2(x-(-2)
y+4 =1/2 (x+2)
now the standard form 2y+8=x+2
so -x+2y=-6 is the equation for line p in standard form
Hello,
y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)
Answer:
0.8
Step-by-step explanation:
A: P(1) = .6, P(2) = .5, P(1 and 2) = .3
P(1 or 2) = P(1) + P(2) - P(1 and 2) .6 + .5 - .3 = 0.8
The sequence is geometric, so

for some constant r. From this rule, it follows that

and we can determine the first term to be

Now, by substitution we have

and so on down to (D)

(notice how the exponent on r and the subscript on a add up to n)
Answer:
(x² -1) + y² = 9
Step-by-step explanation:
diameter=6 so radius means 6/2=3 (thus,radius²=3²=9)
centre (1 and midpoint of diameter is at y=0, so 1,0)