H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.
True I believe since every person has a different temperature and sound waves.
Answer is: the pressure in a vessel is 1.48 atm.
V(Cl₂) = 22.4 L; pressure of chlorine gas.
n(Cl₂) = 1.50 mol; amount of chlorine gas.
T = 0.00°C = 273.15 K; temperature.
a = 6.49 L²·atm/mol²; the constant a provides a correction for the intermolecular forces.
b = 0.0562 L/mol; value is the volume of one mole of the chlorine gas.
R = 0.08206 L·atm/mol·K, universal gas constant.
Van de Waals equation: (P + an² / V²)(V - nb) = nRT.
(P + 6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) · (22.4 L - 1.5 mol·0.0562 L/mol) = 1.5 mol · 0.08206 L·atm/mol·K · 273.15 K.
(P + 6.49 L²·atm/mol² · (1.5 mol)² / (22.4 L)²) = (1.5 mol · 0.08206 L·atm/mol·K · 273.15 K) ÷ (22.4 L - 1.5 mol · 0.0562 L/mol).
P + 0.029 atm = 33.62 L·atm ÷ 22.31 L.
P = 1.507 atm - 0.029 atm.
P = 1.48 atm; the pressure.
2n² rule:
This rule is used to determine number of electrons in particular shell.
n=1 means K shell
n=2 means L shell
n=3 means M shell
n=4means N shell
The first K shell can hold upto 2 electrons, L shell can hold up to 8, third M shell can hold up to 18and the fourth N shell can hold upto 32 electrons. This rule of arrangement of electrons according to the shell is known 2n2 rule where n means number of shell.
For example: There is one proton in the nucleus of hydrogen atom, which moves in K shell path. It has no neutron.
Answer : The mass of sodium carbonate added to neutralize must be, 
Explanation :
First we have to calculate the moles of 
.
Given:
Molar mass of = 98 g/mole
Mass of = 
Conversion used : (1 kg = 1000 g)
Now put all the given values in the above expression, we get:
The moles of is, 
Now we have to calculate the moles of 
The balanced neutralization reaction is:
From the balanced chemical reaction we conclude that,
As, 1 mole of neutralizes 1 mole of
So, of neutralizes
Now we have to calculate the mass of
Molar mass of = 106 g/mole
Thus, the mass of sodium carbonate added to neutralize must be,
