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Lapatulllka [165]
3 years ago
5

In the determination of iron in an ore, the ore (mostly Fe2O3) is first dissolved in HCl(aq). A slight excess of Sn2 is added to

reduce Fe3 to Fe2 . Enter the net ionic equation for the redox reaction.
Chemistry
1 answer:
katovenus [111]3 years ago
8 0

Answer:

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

Explanation:

A redox reaction occurs between a compound that loses electrons and others that gain an electron. The first is being oxidized, and the other is being reduced.

In this situation, in the compound Fe₂O₃, the iron, has an oxidation number equal to +3, so it's Fe⁺³, and it will gain 1 electron to become Fe⁺². Because it was first dissolved in HCl, we must use the ion at the equation. The other compound Sn₂ will be oxidized to Sn⁺², so it will need to lose 2 electrons.

So, it will be necessary 2 Fe⁺³ for this reaction happen:

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

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Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
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<u>Explanation:</u>

We are given:

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                2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)

<u>Initial:</u>          2.00

<u>At eqllm:</u>     2.00-2x          x      x

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6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M

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