Answer:
3.15 × 10⁻⁶ mol H₂/L.s
1.05 × 10⁻⁶ mol N₂/L.s
Explanation:
Step 1: Write the balanced equation
2 NH₃ ⇒ 3 H₂ + N₂
Step 2: Calculate the rate of production of H₂
The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:
2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s
Step 3: Calculate the rate of production of N₂
The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:
2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s
The enzyme must attract substrates to its active state.
At the end of the reaction, products dissociate from the surface of the enzyme
Answer:
b) O₂
d) CH₄
Explanation:
In a chemical equation, the <u>reactants</u> are the substances that are written on the <u>left side</u>. The reactants react to produce the products. On the right side, the products are written.
The arrow => is used to separate the reactants from the products.
To the left of the arrow, you can see this written:
CH₄ + 2O₂
The plus sign + is used to separate each reactant.
In 2O₂ you can ignore the big 2 because it is a coefficient, which is written to balance the equation.
The reactants are CH₄ and O₂
Answer: In the immune responds B,D are correct
Explanation:
I know this because i already learned it
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