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Alex777 [14]
3 years ago
5

How to do for these questions? Help! Thanks :) ​

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Step-by-step explanation:

convert to fractions, then click sd on sure calculator and it converts to decimal for u which u just times 100 to get percentage.

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sukhopar [10]
Yes similar polygons are are two polygons with the same shape but not the same size
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2 years ago
Solve:<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bzz%7D%7B4%7D%20%20%2B%205%20%5Cgeqslant%205.5" id="TexFormula1" title="
allochka39001 [22]

\bf \cfrac{zz}{4} + 5\geqslant 5.5\implies \stackrel{\textit{subtracting 5 from both sides}}{\cfrac{zz}{4}\geqslant 0.5}\implies \stackrel{\textit{multiplying both sides by 4}}{zz \geqslant 2}

7 0
3 years ago
Determine the slope of a line that goes through (2,7) and (11,10)
tia_tia [17]

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1/3

Use the slope formula and simply the fraction.

4 0
2 years ago
CAN SOMEBODY PLEASE HELP ME!!!!!!!!!!
lana66690 [7]

The answers to the blanks are

1. 600,

2. 120,

3. 120,

4. 180.

Explanation:

  • The fence means perimeter around the court. So a tennis court's perimeter is 600 feet fence. The perimeter of a rectangle is 2 times the sum of the rectangle's length and the rectangle's width.
  • It is given that length equals 60 more than width i.e. l = w + 60, where l is the length of the court and w is the width of the court.
  • The perimeter of a court = 600 = 2 (l + w) = 2l + 2w = 2 (w +60) + 2w,                                                                                                     this becomes, 2w + 120 + 2w = 600; 4w = 480, w = 120.
  • Since l = w + 60, l = 120 + 60 = 180. So length of a court is 180 feet and the width of a court is 120 feet.

6 0
2 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
Read 2 more answers
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