We’ll subtract the exponent in the denominator from the exponent in the numerator, keeping the base the same. Cant be simplified, because the base of the expression in the numerator is y and the base of the expression in the denominator is x.
The answer to your question is Y=12
Answer:
8x²- x -8
Step-by-step explanation:
The question is not well written. I guess what you mean is:
Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).
To subtract -2x^2+4x-1 from 6x^2+3x-9, that is
6x^2+3x-9 - (-2x^2+4x-1). This can be written as
6x²+3x-9 - (-2x²+4x-1)
Now, opening the bracket, we will get
6x²+3x-9 +2x²-4x+1
Then, collecting like terms, we get
6x²+2x²+3x-4x-9+1
6x²+2x² = 8x²
3x-4x = -x
-9+1 = -8
∴6x²+2x²+3x-4x-9+1 becomes
8x²-x -8
The answer is 8x²-x -8.
You times 4 by everything inside the parentheses, so the answer would be as follows. 16a + 20b - 12
Step-by-step explanation:
roots as exponents are fractions
if there is no root number next to the radical sign its assumed that its 1/2
3√2 is 2^(1/3)
√3 is 3^(1/2)
4√3 is 3^(1/4)
5√2 is 2^(1/5)
