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Nadusha1986 [10]
2 years ago
13

art teacher has 450 sheets of construction paper on first day of school. students used 18 sheets during each school day. how man

y school days did the construction paper last?
Mathematics
1 answer:
AVprozaik [17]2 years ago
7 0

Answer:

25

Step-by-step explanation:

025

18 |450

- 36

090

- 90

00

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dimaraw [331]

Answer:

<h2>FALSE</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>tips and formulas:</h3>

order of PEMDAS

  1. parentheses
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  3. multiplication or
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  5. addition
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<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
  1. <u>\sf simplify  \: divition:  \\  \tt 14 + 33 + 0.4</u>
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therefore

<h3>the equality is false</h3>

8 0
3 years ago
WHAT'S THE ERROR? A student says 3(n- 5) is equal to 3n - 5. What's<br>the error?​
inn [45]

Answer:

The student incorrectly used the Distributive property!

Step-by-step explanation:

The Distributive property says a(b+c)=ab+ac

In this problem the answer SHOULD be 3n-15, however the <u>student forgot to distribute the 3 to the -5</u>!

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3 years ago
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Many high school students take the AP tests in different subject areas. In 2007, of the 144,796 students who took the biology ex
Nataly [62]

Answer:

(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942  

(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978  

And the 90% confidence interval would be given (0.0942;0.09978).  

We are confident at 90% that the difference between the two proportions is between 0.0942 \leq p_A -p_B \leq 0.09978

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion female for Biology

\hat p_A =\frac{84199}{144796}=0.582 represent the estimated proportion female for biology

n_A=144796 is the sample size for A

p_B represent the real population proportion female for calculus AB

\hat p_B =\frac{102598}{211693}=0.485 represent the estimated proportion female for Calculus AB

n_B=211693 is the sample size required for B

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

And replacing into the confidence interval formula we got:  

(0.582-0.485) - 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.0942  

(0.582-0.485) + 1.64 \sqrt{\frac{0.582(1-0.582)}{144796} +\frac{0.485(1-0.485)}{211693}}=0.09978  

And the 90% confidence interval would be given (0.0942;0.09978).  

We are confident at 90% that the difference between the two proportions is between 0.0942 \leq p_A -p_B \leq 0.09978

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Answer:

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Step-by-step explanation:

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