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wariber [46]
3 years ago
11

2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th

at he must stop at the first signal is 0.36, the analogous probability for the second signal is 0.54, and the probability that he must stop at at least one of the two signals is 0.65. What is the probability that he must stop at exactly one signal?
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

P(stop 1) = P(x) = 0.36

Probability of stopping at second signal = 0.54;

P(stop 2) = P(y) = 0.54

Probability of stopping at atleast one of the two signals:

P(x U y) = 0.6

Stopping at both signals :

P(xny) = p(x) + p(y) - p(xUy)

P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06

Stopping at y but not x

P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30

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From the question, we have the following parameters:

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When the number of apple trees is increased (say by x).

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Set P'(x) to 0

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Read more about quadratic functions at:

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1 year ago
Can anyone help me get the correct answer?
Andreyy89

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Step-by-step explanation:

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Answer:

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Answer:

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next we want to subtract 2w from both sides making the equation 6w=-7u then we divide by 6 to get w=-1.16u

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