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Eddi Din [679]
2 years ago
8

Pls help i will give brainliest!!!!! :)

Mathematics
1 answer:
Zigmanuir [339]2 years ago
5 0

Answer: c.50 is the answer

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PLEASE HELPP MEEEEE
pav-90 [236]
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.

Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11

Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
6 0
3 years ago
Find the value of 1225 by using prime factorization
pashok25 [27]

i hope it is helpful ti youu

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3 years ago
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elena-14-01-66 [18.8K]
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3 years ago
If x^2=20 what is the value of x
tankabanditka [31]

Answer:

Step-by-step explanation:

x^2=20

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Angle Bisector Solve for Y
olganol [36]

As <ABC=40

3x-1+34-2x=40

x =40-34+1 = 7

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3y= 180-95-21=64

Y =64/3

4 0
3 years ago
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