Answer:
C 200
Step-by-step explanation:
It does not appear to be LINEAR so
Start with :
pulse rate = y = 73e^kx
sub in x = .7 when y = 155
155 = 73 e^(.7 * k)
ln ( 155/73) = .7k
.75296567 = .7k
k = 1.07567
for x = 0.9 :
pulse rate = y = 73 e^(1.07567 * .9) = ~ 192 so I expect answer is 200
Answer:
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
Set up equation before taxes.
y = x - 1500 eq1
Set up equation for total tax paid.
0.065x + 0.06y = 378.75 eq2
Substitute eq1 into eq2.
0.065x + 0.06(x - 1500) = 378.75
0.065x + 0.06x - 90 = 378.75
0.125x - 90 = 378.75
0.125x = 468.75
x = 3750
Substitute this value of x into eq1.
y = 3750 - 1500
y = 2250
The hotel charge in city one is $3750 and the hotel charge in city two is $2250
Answer:
24
Step-by-step explanation:
Answer:
multiply
Step-by-step explanation:
just multiply all of them and then u will get your answer I hope this helped ❤
Answer:
x = - 1 ± 2i
Step-by-step explanation:
we can use the discriminant b² - 4ac to determine the nature of the roots
• If b² - 4ac > , roots are real and distinct
• If b² - 4ac = 0, roots are real and equal
• If b² - ac < 0, roots are not real
for x² + 2x + 5 = 0
with a = 1, b = 2 and c = 5, then
b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16
since b² - 4ac < 0 there are 2 complex roots
using the quadratic formula to calculate the roots
x = ( - 2 ± 
) / 2
= (- 2 ± 4i ) / 2 = - 1 ± 2i
