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mixas84 [53]
4 years ago
6

Help fast big bonus if get right due soon !!

Mathematics
2 answers:
diamong [38]4 years ago
5 0
Multiply the the numbers for each locket and see which number is greater
Alekssandra [29.7K]4 years ago
4 0
School Locker is 7,200 cubic inches. Gym Locker is 8,640 cubic inches.
You might be interested in
Which quadratic function has a leading coefficient of 2 and a constant term of –3?
Romashka [77]
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

<u>We are looking for a = 2, c = -3</u>

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
6 0
3 years ago
Read 2 more answers
Select all expressions whose value is negative
il63 [147K]

Answer:

"2 + 2(-3)(7) = negative

-2(27 ÷ 9)+4= negative

(14 ÷ -2)(-6)= positive

(4 - 10) - ( 8 ÷ ( -2))= negative

Step-by-step explanation:

2 + 2(-3)(7) = -40

-2(27 ÷ 9)+4= -2

(14 ÷ -2)(-6)= 42

(4 - 10) - ( 8 ÷ ( -2))= -2"

5 0
4 years ago
I need help with this question on my hw
PtichkaEL [24]

Answer:

A) 630 feet squared

Step-by-step explanation:

6 0
3 years ago
What is the greatest whole number that will divide both 792 and 990 exactly
Nastasia [14]
Factor the numbers, starting from the smallest:
792=2*3*3*11*4
990=2*3*3*11*5
the greatest whole number that can be divided by both 792 and 990 is 2*3*3*11=198
the smallest whole number that can divide both 792 and 990 exactly is 2*3*3*11*4*5=3960

Not sure which one you are asked to find. 
8 0
3 years ago
Read 2 more answers
How many real solutions if any, does 2x^2-3x+8=0​
fenix001 [56]

Answer:

The quadratic equation 2\, x^{2} - 3\, x + 8 = 0 has no real solution.

Step-by-step explanation:

Rewrite the quadratic equation 2\, x^{2} - 3\, x + 8 = 0 in the standard form a\, x^{2} + b\, x + c = 0:

2\, x^{2} + (-3)\, x + 8 = 0, for which:

  • a = 2.
  • b = (-3).
  • c = 8.

The quadratic discriminant of a\, x^{2} + b\, x + c = 0 is (b^{2} - 4\, a\, c).  The quadratic discriminant of 2\, x^{2} + (-3)\, x + 8 = 0 would be:

\begin{aligned}& b^{2} - 4\, a\, c \\ =\; & (-3)^{2} - 4 \times 2 \times 8 \\ =\; & (-55)\end{aligned}.

Since the quadratic discriminant of this equation is negative, this quadratic equation has no real solution.

3 0
2 years ago
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