y=5/6+3
I am not positive on this answer I am sorry if it is wrong
First you have to distribute. -3y +12=18. -3y=6. y= -2.
Given that the distance between two lines in the measurement instrument is 0.01m, the maximum error should be 0.01m/2 = 0.005 m.
If you do a good work, the real measure is 1.20m +/- 0.005m, this is between 1.195 and 1.205.
Answer: 50%
Step-by-step explanation: