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stepladder [879]
3 years ago
12

How do i find the slope if one point is (0,-3) and the other is (4,-1)

Mathematics
2 answers:
lyudmila [28]3 years ago
5 0
-1 + 3/ 4-0 simplify equals 2/4=1/2 so the answer is 1/2
Gennadij [26K]3 years ago
4 0
Y2-y1 divided by x2-x1 so -1--3 over 4-0 so it is 2/4 or 1/2
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a_n=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{n-1}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{-1}\cdot\left(\frac{1}{2}\right)^n=\frac{3}{2}\cdot2\cdot\left(\frac{1}{2}\right)^n=3\cdot\left(\frac{1}{2}\right)^n
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Definition of piggle
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Closed shape, do not intersect - geometry definition
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What is the value of tan D ?
4vir4ik [10]

Answer:

12/5

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8 0
3 years ago
Read 2 more answers
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
Round 3.251 to the hundredths place.
aliya0001 [1]
It would be 3.25 because you can’t round 0.001 up
4 0
3 years ago
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