Answer:
The rate of change will be the same for all years.
Step-by-step explanation:
As it is mentioned in the question, that the rate of change is 7%.
And as we know that
= I (1 + R)^T
where
I = Initial amount
R = Rate of growth,
And T = Time.
So in the given case, the rate is 0.07, or 7% while on the other hand the growth RATE remains constant and the growing amount would be increased each year.
Therefore the rate of change would be the same for all the year
Answer:
ciao anyways
Step-by-step explanation:
T = 1/5(x - y + z)
First, let's get rid of the 1/5. To do this, you can multiply both sides by the reciprocal, or 5/1.
(5/1)T=[(5/1)1/5](x-y+z)
5T = x - y + z
Now subtract x from both sides.
5T - x = -y + z
Add y to both sides.
5T - x + y = z
So the answer is:
z = 5T - x + y
Answer:
a). Y = y0e^-k(t)
b) Y = 19.4 Unit mass
Step-by-step explanation:
Y = y0e^-k(t)
Where y is amount present at the time
Y0 is initial amount present at t = 0
Y0 = 58.7
Half life = 5 hours
At half life , y = 58.7/2
At half life , y = 29.35
K = decaying constant.
Let's look fithe value of k
Y = y0e^-k(t)
29.35 = 58.7e^-k(5)
29.35/58.7 = e^-k(5)
0.5 = e^-k(5)
In 0.5 = -k(5)
-0.69314718 = -k(5)
0.138629436 = k
The value present in 8 hours will be
Y = y0e^-k(t)
Y = 58.7e-0.138629436(8)
Y = 58.7e-1.109035488
Y = 58.7(0.329876978)
Y= 19.36377861
To the nearest tenth
Y = 19.4 unit of mass