Answer:
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 64 - 1 = 63
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 63 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.387
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.99 - 0.02 = 2.97 liters
The upper end of the interval is the sample mean added to M. So it is 2.99 + 0.02 = 3.01 liters
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.
Answer:
D (13,5)
Step-by-step explanation:
X 2 3 4 5
Y 2 5 9 13
So the ordered pairs are (2,2),(3,5), (4,9), (5,13)
and the ordered pairs for the inverse are
(2,2),(5,3), (9,4), (13,5)
from which D (13,5) is found among the options.
Answer:
Third sequence (7, 2, 1, -4, -10)
In the first sequence, -4 has to be in front of -10 because it is larger.
In the second sequence, 7 goes in the beginning, with 2 then 1 following, with -4 behind and -10 behind -4.
In the third option, 7 must be in the front, with 2, 1, then -4, then -10 following.
The answer = third sequence.
Hope it helped!
Answer:
8) answer=5 9)answer=15
Step-by-step explanation:
all you have to do is replace in the following formula
Where
X1: is the first number of the first point
Y1: is the second number of the first point
X2: is the first number of the second point
Y2: is the second number of the second point
you replace in the formula and solve
I attach solution
Answer:
The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).
