If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Im not sure if you are saying 74/5 or 7 and 4 fifths but in the case you'r saying 74/5 you would first round to see the highest number that 5 can go to without being a decimal. Which would be 70 so you would count how many times 5 can go into 70, which would be 14, so the left over is 4/5 so you would check to see if it can be simplified which it can't so the final answer is 14 and 4/5
Answer:
Letter c is the answer
Step-by-step explanation:
Sorry if my answer is wrong
That sequence is not geometric or arithmetic
it is not changing or doing anything it is just remaining the same.
it would be geometric if it was:
1+1-1+1-1+1........
Answer:
16
Step-by-step explanation:
4 flavors
2 toppings
2 containers
4x 2= 8
8x2=16
