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wel
3 years ago
11

Find the Tolal Surface Area​

Mathematics
2 answers:
Yakvenalex [24]3 years ago
7 0
The answer to this question would be C , Hope I helped :)
julia-pushkina [17]3 years ago
3 0
The answer is c hope this helped
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A restaurant offers four sizes of pizza, two types of crust, and eight toppings. How many possible types of pizza with one toppi
valentina_108 [34]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
William purchased 76.9 feet of fencing for his back yard. He realized after measuring, that he still needed an additional 25.7 f
Lostsunrise [7]
William needs 102.6 fencing in all because 76.9 plus 25.7 equals 102.6, hope this helps!
3 0
3 years ago
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
What is 1×3+45÷1×0=​
QveST [7]
The answer to this equation would be 3.
7 0
3 years ago
Read 2 more answers
Revenue is 3,000,cost of goods is 1,500, selling expense is 500 what is the prophit?
tia_tia [17]
In this situation the revenue is the total sales you make before all expenses.
To find the profit: 3000 - 1500 - 500 = 1000.
Your profit is $1,000.
4 0
3 years ago
Read 2 more answers
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